divide data to 100 input files
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I have a numeric data set as a 1xn (for example 1x32768) matrix, and I want to divide it into m files (for example 100 files) and making directories and send each file to corresponding directory. I did use the following code: reshape(Data,[],100); but problem is 32768 is not divisible to 100. is there any way for solve my issue? or I have to reduce my data to 32700? Any help is appreciated.
3 个评论
Walter Roberson
2016-5-16
What do you want to have happen with the block of 68?
Holden Caulfield
2016-5-17
Walter Roberson
2016-5-17
If you need to do this for each data set, why are you grouping them into 100's ?
回答（2 个）
Aritra Sasmal
2016-5-16
编辑：Walter Roberson
2016-5-16
I don't understand why you want to reshape it but here's how you'd do it if you wanted to form a matrix like you have;
n=size(Data,1);
Mat=zeros(100,ceil(n/100));
Mat(:,1:floor(n/100))=reshape(Data(1:floor(n/100)),[],100);
Mat(1:(n%100),end)=Data(floor(n/100)+1:end);
This would create the 100 row matrix that you want.
However, you can just write a loop
i=1:ceil(n/100)
put stuff in an array and save as ascii file and close the filw pointer
end
This would package the data into smaller files in a loop
2 个评论
Holden Caulfield
2016-5-17
Walter Roberson
2016-5-17
The code Aritra posted does have a conflict between 100 rows and 100 columns.
Walter Roberson
2016-5-16
For numeric row matrix M,
block = 100;
blocked = mat2cell(M, 1, [block * ones(1, floor(M/block)), mod(M, block)]);
1 个评论
Walter Roberson
2016-5-17
If you have a numeric matrix you want to rearrange into groups of fixed size, see buffer()
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