"Undefined function or variable 'x'." for input of function
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I had a function which was working perfectly for a while, however suddenly stopped working. The function is to plot a 2D vector field with inputs of the components in the x-direction (i) and y-direction (j) as well as mins and maxes.
function [ output ] = VecField(i,j,min,max)
% SCRIPT FOR PLOTTING VECTOR FIELDS
% Use defined range to create matrix of x,y values.
[x,y] = meshgrid(min:20:max);
% Plot vectors
quiver(x,y,i,j,'color','red','linewidth',1.2)
% Define axes based on given range
if min > 0
min_axes = 0.95*min;
else
min_axes = 1.05*min;
end
if max > 0
max_axes = 1.05*max;
else
max_axes = 0.95*max;
end
% Graph configuration
axis([min_axes max_axes min_axes max_axes])
title('Velocity vector field plot of over cylinder (inviscid)')
xlabel('x-axis')
ylabel('y-axis')
end
An example input which was previously working is: VecField(((-x-y)./((x.^2+y.^2).^0.5)),((x-y)./((x.^2+y.^2).^0.5)),-200,200)
While I can understand the error (Undefined function or variable 'x'.), I am unsure how to remedy it. If I enclose the functions in quotation marks, then the quiver function can no longer handle the inputs.
Are there any simple ways of getting around this?
3 个评论
Curtnos
2016-5-21
Sorry, I should have elaborated on the use of the code! The initial two values must be functions of x and y. After calling the function with these the array of x and y values are created (meshgrid) and then applied to each 'i' and 'j' which forms the input arrays for the quiver function. So numbers won't be a valid input for the quiver function. Here is an example of what it should put out:
dpb
2016-5-21
Amplifying Stephen's comment, I don't see anything wrong w/ x,_y_ in your function but from
help quiver
...
quiver(X,Y,U,V) plots velocity vectors as arrows with components (u,v)
at the points (x,y). The matrices X,Y,U,V must all be the same size...
Your function creates a 2D grid for the positions, but passes in i and j which should be the velocity components. Looks peculiar; should they probably not also be output from meshgrid, perhaps???
Also, you have an [output] argument, but it is never defined???
Curtnos
2016-5-21
采纳的回答
1) When I run your code exactly as it is I get a totally different error:
>> VecField(1,2,0,100)
??? Error using ==> quiver at 58
The size of X must match the size of U or the number of columns of U.
So you need to clarify how you calling this function, and with what values.
2) Note that the quiver documentation clearly states that its input matrices must be of the same size: " quiver(x,y,u,v) plots vectors as arrows at the coordinates specified in each corresponding pair of elements in x and y. The matrices x, y, u, and v must all be the same size." There is absolutely nothing in your code to check or ensure that these matrices are the same size, so presumably it was only luck that allowed that function to work previously.
3) Also note that your variable names go from not-reccomended to extremely bad: you should never use the variable names i and j because these are the names of the inbuilt imaginary unit, and using the names min and max makes the inbuilt functions with the same names stop working: this could easily produce pointless bugs later. Change your variable names!
4) Get rid of the output variable: if you don't use, then don't define it.
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