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splitting matrix to different row

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Ali
Ali 2016-5-26
评论： Ali 2016-5-26
I have the following matrix and I want to split it.
A=[0 2 4 ,5 0 4]
it should be like this:
[0 2]
[2 4]
[4 2]
[5 0]
[0 4]
[4 5]
Please write me, If you have answer. Thanks
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Ali
Ali 2016-5-26
编辑：Ali 2016-5-26
Many thanks for the response.. I wrote it wrong.
I have a matrix with 260 row and 3 columns. I would like to produce a matrix with 780 row and 2 columns. for instance:
A=[0 2 4; 5 0 4]
I would like to have something like this:
[0 2]
[2 4]
[4 0]
[5 0]
[0 4]
[4 5]
the cyclist
the cyclist 2016-5-26
I was sent the following via email. I think it is a clearer statement of the request:
# Elements
1 0 2
0 3 2
4 1 6
6 1 2
3 5 7
3 7 2
6 2 7
8 4 6
I would like to have this:
1 0
0 2
2 1
0 3
3 2
2 0
4 1
1 6
6 4
6 1
1 2
2 6
3 5
5 7
7 3
3 7
7 2
2 3
6 2
2 7
7 6
8 4
4 6
6 8

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the cyclist
the cyclist 2016-5-26
编辑：the cyclist 2016-5-26
Trying to piece together all the guesses that these kind volunteers have made in trying to help you. Does this do what you want?
A = [0 2 4; 5 0 4];
At = A';
chunkSize = size(A,2);
shiftedIndex = bsxfun(@plus,mod(1:chunkSize,chunkSize)',[0:chunkSize:numel(At(:))-chunkSize]) + 1;
B = [At(:) At(shiftedIndex(:))]
[ EDIT: I changed this code to correspond to what I wrote in my comment below. Given the new information you provided, I think this is correct.]
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Ali
Ali 2016-5-26
Many thanks for the help.
what about the number in front of each row?
for instance:
1: 0 2
tnx again
Ali
Ali 2016-5-26
Thanks a lot the cyclist!

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