help with image filtering

3 次查看（过去 30 天）

rajashekar 2012-2-9

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/28608-help-with-image-filtering

编辑： Image Analyst 2013-10-7

hi everyone, i'm tring to use a grayscale image as a message and modulate it with a carrier. then i receive it, demodulate it and filter it to remove the carrier to see the original image. i used a butterworth low pass and fspecial('motion'); filter and then "imfilter" to filter the image. but the image i get after filtering with these is not sharp as original. also i'm using a grayscale image,after filtering the white in original is turning black and vice versa.

can someone suggest me a better filter or fix to this problem?

thanks....

4 个评论
显示 2更早的评论隐藏 2更早的评论

Image Analyst 2012-2-10

OK, then it would be nice if you had supplied more information for this question, if it's a stand alone, unrelated issue. I'm not even sure what the "fix" would be. Would it be to have the white pixels not be black, or not be blurry? Is the modulation part working, or is not even that part working?

Walter Roberson 2012-2-10

Is this current question just the static picture equivalent of the previous question? If so then the main difference appears to be just that you are apparently not using an analog step in this question (which does save you a lot of effort of trying to do useful modulation / demodulation on a NTSC signal.)

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

Image Analyst 2012-2-9

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/28608-help-with-image-filtering#answer_36938

I don't see how your series of filters does anything like your algorithm. I don't see modulation with any carrier, and your filtering just low pass filters the image so of course it's blurry.

4 个评论
显示 2更早的评论隐藏 2更早的评论

rajashekar 2012-2-10

ideas?

Image Analyst 2012-2-10

About...? About why you didn't post code? Not really. By the way, I'm not really expert about modem (modulation/demodulation) functionality, so I probably won't be able to help you on that part.

请先登录，再进行评论。

请先登录，再回答此问题。