What is the problem with this for loop?
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deltaK values are should be "zero" for clock time of 0 - 0.999 sec but its giving the values of 0.1.Please help to solve the issue.
function [Out] = LMAImplementation_Motor(In)
persistent eWithNoChange eWithDeltaL eWithDeltaK
e = In(1);
L = In(2);
K = In(3);
Clock = In(4);
clock = int64(Clock)
for clock = 0.000:0.999
deltaK = 0; deltaL = 0;
eWithNoChange(end+1) = e;
sizeofeWithNoChange = size(eWithNoChange);
end
for clock = 1.000:1.999
deltaL = L*0.1; deltaK = 0;
eWithDeltaL(end+1) = e;
sizeofeWithDeltaL = size(eWithDeltaL);
end
for clock = 2.000:2.999
deltaL = 0; deltaK = K*0.1;
eWithDeltaK(end+1) = e;
sizeofeWithDeltaK = size(eWithDeltaK);
end
deltaK
deltaL
Out = [deltaL,deltaK,Clock];
end
I don't understand why the deltaK values is 0.1 even when the clock values in between 0 and 0.999.
回答（1 个）
Roger Stafford
2016-6-5
0 个投票
For each of the for-loops ‘clock’ can take only one value. For example, with "for clock = 1.000:1.999", clock can only be 1.000, since the default step size is 1. I think you meant "for = 1.000:0.001:1.999".
4 个评论
kintali narendra
2016-6-5
In the simulation the step size is 0.0001
and clock is given to Zero-order hold to match the simulation step size
Roger Stafford
2016-6-5
OK, then you should have said
for = 1.000:0.0001:1.999
kintali narendra
2016-6-5
Roger Stafford
2016-6-5
You are not using 'clock' anywhere in your for-loops. Your 'e' is zero, so you are stretching 'eWithNoChang' out in long vectors of zeros and nothing else is accomplished. You had better stop and rethink what it is you are trying to do.
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2016-6-5
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