How to replace values in a matrix?

2016 6 6
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更新时间：2016 6 6
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Hello everyone, I am new in matlab and I need help please.
I have a matrix A that contains probability distribution( size : 7*8).there is the matrix :
A=[ 0.2 0.07 0.25 0.87 0.09 0.14 0.8 0.3;
0.1 0.5 0.25 0.14 0.98 0.025 0.58 0.11;
0.001 0.25 0.88 0.21 0.03 0.25 0.58 0.25;
0.26 0.58 0.001 0.06 0.9 0.58 0.44 0.15;
0.12 0.58 0.16 0.08 0.15 0.47 0.33 0.15;
0.15 0.22 0.3 0.14 0.01 0.99 0.77 0.55;
0.003 0.25 0.14 0.99 0.005 0.85 0.26 0.003;
];
I have also a matrix B (size 7*4) that contains such A probabilities and matrix C (size 7*4) that contains positions.
B=[ 0.25 0.55 0.15 0.02;
0.001 0.25 0.33 0.04;
0.2 0.3 0.11 0.58;
0.25 0.14 0.77 0.69;
0.88 0.59 0.58 0.001;
0.02 0.3 0.7 0.8;
0.3 0.9 0.66 0.11;]
C= [ 8 2 4 1
1 2 3 4
7 5 2 8
1 2 3 4
2 4 3 7
1 5 6 7
2 8 4 1]
My goal is to replace values in A with values in the matrix B according to the position in C, I will have as result this matrix (size 7*8) :
NewA=[ 0.02 0.55 0.25 0.15 0.09 0.14 0.08 0.25
0.001 0.25 0.33 0.04 0.98 0.025 0.58 0.11
0.001 0.11 0.88 0.21 0.3 0.25 0.2 0.58
0.25 0.14 0.77 0.69 0.9 0.58 0.44 0.15
0.12 0.88 0.58 0.59 0.15 0.047 0.001 0.15
0.02 0.22 0.3 0.14 0.21 0.7 0.8 0.55
0.11 0.3 0.14 0.66 0.005 0.85 0.26 0.9]
Please, any idea, How Can I do it? and thanks in advance

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 采纳的回答

Image Analyst
Image Analyst 2016-6-6

0 个投票

Try a simple for loop:
A=[ 0.2 0.07 0.25 0.87 0.09 0.14 0.8 0.3;
0.1 0.5 0.25 0.14 0.98 0.025 0.58 0.11;
0.001 0.25 0.88 0.21 0.03 0.25 0.58 0.25;
0.26 0.58 0.001 0.06 0.9 0.58 0.44 0.15;
0.12 0.58 0.16 0.08 0.15 0.47 0.33 0.15;
0.15 0.22 0.3 0.14 0.01 0.99 0.77 0.55;
0.003 0.25 0.14 0.99 0.005 0.85 0.26 0.003;
];
B=[ 0.25 0.55 0.15 0.02;
0.001 0.25 0.33 0.04;
0.2 0.3 0.11 0.58;
0.25 0.14 0.77 0.69;
0.88 0.59 0.58 0.001;
0.02 0.3 0.7 0.8;
0.3 0.9 0.66 0.11;]
C= [ 8 2 4 1
1 2 3 4
7 5 2 8
1 2 3 4
2 4 3 7
1 5 6 7
2 8 4 1]
[rows, columns] = size(B)
newA = A; % Initialize.
for row = 1 : rows
newA(row, C(row,:)) = B(row, :);
end
newA % Print in command window to verify

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