How to replace values in a matrix?

Question

aya ben mabrouk 2016-6-6

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/287865-how-to-replace-values-in-a-matrix

评论： aya ben mabrouk 2016-6-6

采纳的回答： Image Analyst

在 MATLAB Online 中打开

Hello everyone, I am new in matlab and I need help please.

I have a matrix A that contains probability distribution( size : 7*8).there is the matrix :

 A=[ 0.2 0.07 0.25 0.87 0.09 0.14 0.8 0.3;
1 0.5 0.25 0.14 0.98 0.025 0.58 0.11;
001 0.25 0.88 0.21 0.03 0.25 0.58 0.25;
26 0.58 0.001 0.06 0.9 0.58 0.44 0.15;
12 0.58 0.16 0.08 0.15 0.47 0.33 0.15;
15 0.22 0.3 0.14 0.01 0.99 0.77 0.55;
003 0.25 0.14 0.99 0.005 0.85 0.26 0.003; 
   ];

I have also a matrix B (size 7*4) that contains such A probabilities and matrix C (size 7*4) that contains positions.

 B=[ 0.25 0.55 0.15 0.02;
001 0.25 0.33 0.04;
2 0.3 0.11 0.58;
25 0.14 0.77 0.69;
88 0.59 0.58 0.001;
02 0.3 0.7 0.8;
3 0.9 0.66 0.11;]
C= [ 8 2 4 1
2 3 4
5 2 8
2 3 4
4 3 7
5 6 7
8 4 1]

My goal is to replace values in A with values in the matrix B according to the position in C, I will have as result this matrix (size 7*8) :

 NewA=[ 0.02 0.55 0.25 0.15 0.09 0.14 0.08 0.25
        0.001 0.25 0.33 0.04 0.98 0.025 0.58 0.11
        0.001 0.11 0.88 0.21 0.3 0.25 0.2 0.58
        0.25 0.14 0.77 0.69 0.9 0.58 0.44 0.15
        0.12 0.88 0.58 0.59  0.15  0.047 0.001 0.15
        0.02 0.22 0.3 0.14 0.21 0.7 0.8 0.55
        0.11 0.3 0.14 0.66 0.005 0.85 0.26 0.9]
Please, any idea, How Can I do it? and thanks in advance

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Answer 1

Image Analyst 2016-6-6

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https://ww2.mathworks.cn/matlabcentral/answers/287865-how-to-replace-values-in-a-matrix#answer_224556

在 MATLAB Online 中打开

Try a simple for loop:

A=[ 0.2 0.07 0.25 0.87 0.09 0.14 0.8 0.3;
  0.1 0.5 0.25 0.14 0.98 0.025 0.58 0.11;
  0.001 0.25 0.88 0.21 0.03 0.25 0.58 0.25;
  0.26 0.58 0.001 0.06 0.9 0.58 0.44 0.15;
  0.12 0.58 0.16 0.08 0.15 0.47 0.33 0.15;
  0.15 0.22 0.3 0.14 0.01 0.99 0.77 0.55;
  0.003 0.25 0.14 0.99 0.005 0.85 0.26 0.003;
  ];
B=[ 0.25 0.55 0.15 0.02;
  0.001 0.25 0.33 0.04;
  0.2 0.3 0.11 0.58;
  0.25 0.14 0.77 0.69;
  0.88 0.59 0.58 0.001;
  0.02 0.3 0.7 0.8;
  0.3 0.9 0.66 0.11;]
C= [ 8 2 4 1
  1 2 3 4
  7 5 2 8
  1 2 3 4
  2 4 3 7
  1 5 6 7
  2 8 4 1]
[rows, columns] = size(B)
newA = A; % Initialize.
for row = 1 : rows
  newA(row, C(row,:)) = B(row, :);
end
newA % Print in command window to verify