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Assign matrix names using for loops in formula

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peterhack
peterhack 2016-6-9
评论： Stephen23 2016-6-9
Hi,
I was wondering how to get my code shorter and cleaner as I am basically using the same formula.
A = zeros(1,t);
B = zeros(1,t);
C = zeros(1,t);
D = zeros(1,t);
E = zeros(1,t);
for z = 1:1:t
if z == 1
A(:,z) = v1;
B(:,z) = v2;
C(:,z) = v3;
D(:,z) = v4;
E(:,z) = v5;
else
A(:,z) = A(:,z-1)*(1+rf);
B(:,z) = B(:,z-1)*(1+rf);
C(:,z) = C(:,z-1)*(1+rf);
D(:,z) = D(:,z-1)*(1+rf);
E(:,z) = E(:,z-1)*(1+rf);
end
end
However, I am aware of better not to use eval.
But I do not get it working using an cell array like here with names = {'A' 'B' 'C' 'D' 'E'}. vx are just some values, which I coul also loop from an array.
Thanks in advance!
  1 个评论
Stephen23
Stephen23 2016-6-9
You are right to avoid eval, which is almost always a bad idea, especially with trivial looped code like this, no matter how much beginners seem attracted to using it:
http://www.mathworks.com/matlabcentral/answers/196952-how-to-create-new-variables-in-batches-with-strcat
The solution is to use indexing. That is all. There is no magic trick, just learn to use the dimensions of ND arrays, or cell arrays, or whatever array suits your needs, and use indexing.

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Jos (10584)
Jos (10584) 2016-6-9
编辑：Jos (10584) 2016-6-9
Remember: It is the contents of the variable that should be flexible, not its name!
You will be way better off using arrays (regular, structs, or cells).
ABCDE = zeros(t, 5)
ABCDE(:,1) = [v1 v2 v3 v4 v5] ;
for z = 2:1:t
ABCDE(:,z) = ABCDE(:,z-1) .* (1+rf) ; % not sure what rf is, hence the .*
end

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