How to Split Data Into Groups Based on Number of Elements in Cell?

Question

Brian Tomblin 2016-6-9

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/288909-how-to-split-data-into-groups-based-on-number-of-elements-in-cell

编辑： Brian Tomblin 2016-6-9

I am incredibly new to Matlab, so any help would be appreciated!

After running a program, I am given a long row of cells with between 1 and 40 individual values within each cell. Cells that have 7 or less numerical elements need to go through a different function than cells that have more than 7 numbers. There are no categories defined for the cells.

What can I write to have Matlab, after receiving the data in a 1xN cell array, determine how many elements are in each cell and separate the cells to then be handled differently?

Thanks.

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Answer 1

Ian Adler 2016-6-9

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/288909-how-to-split-data-into-groups-based-on-number-of-elements-in-cell#answer_225003

在 MATLAB Online 中打开

creating an example cell

    a=cell(2);
    a(1,1)={54};
    a(2,1)={20155};
    a(1,2)={12};
    a(2,2)={15485};

Converting it to a table so we can use it

b=cell2table(a);

Declaring some variables for later user

    x=1;
    y=1;
 for x=1:height(b) %choose either height or width whichever is longer
        if (numel(num2str(b.a1(x,y))) <= 2) == 1

if (the number of characters in (the string version of (cell b.column a1))) is less than 2) is TRUE

            disp([num2str(x) ',' num2str(y) ' is <= 2 numbers']);
 %display ([the character version of (x), the a ',', etc])
        end
        if (numel(num2str(b.a1(x,y))) >= 3) == 1

repeat for cell b. column a1 but if its greater than 3

            disp([num2str(x) ',' num2str(y) ' is >= 3 numbers']);
        end
        if (numel(num2str(b.a2(x,y))) <= 2) == 1 %repeat for cell b column a2
            disp([num2str(x) ',' num2str(y) ' is <= 2 numbers']);
        end
        if (numel(num2str(b.a2(x,y))) >= 3) == 1 %again as above
            disp([num2str(x) ',' num2str(y) ' is >= 3 numbers']);
        end
    end
end

My full code so you can copy and paste and play around wit it

    a=cell(2);
    a(1,1)={54};
    a(2,1)={20155};
    a(1,2)={12};
    a(2,2)={15485};
    %creating an example cell
    b=cell2table(a);
    %converting it to a table
    x=1;
    y=1;
    for x=1:height(b) %choose either height or width whichever is longer
        if (numel(num2str(b.a1(x,y))) <= 2) == 1 %if (the number of characters in (the string version of (cell b.column a1))) is less than 2) is TRUE
            disp([num2str(x) ',' num2str(y) ' is <= 2 numbers']); %display ([the character version of (x), the a ',', etc])
        end
        if (numel(num2str(b.a1(x,y))) >= 3) == 1 %repeat for cell b. column a1 but if its greater than 3
            disp([num2str(x) ',' num2str(y) ' is >= 3 numbers']);
        end
        if (numel(num2str(b.a2(x,y))) <= 2) == 1 %repeat for cell b column a2
            disp([num2str(x) ',' num2str(y) ' is <= 2 numbers']);
        end
        if (numel(num2str(b.a2(x,y))) >= 3) == 1 %again as above
            disp([num2str(x) ',' num2str(y) ' is >= 3 numbers']);
        end
    end

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Brian Tomblin 2016-6-9

编辑：Brian Tomblin 2016-6-9

So this determines the amount of numbers in a value for each cell (if I'm running it correctly on my end). What I'm looking for is to determine the amount of values in a cell, not the size of the number.

Ex. {1,1} = (1,2,1,2,2,3,1) {1,2} = (1,2,3,2,1,2,3,1,3,1,2,3,1,2) I need cells that have 7 or less values (like {1,1}) to be differentiated from cells that have more than 7 values (like {1,2}) so I can, for example, take the mean in cells with 7 or less while ignoring the cells with more than 7.

Does your example work for that idea?

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