I am having trouble adding [a]+[b].
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theta=30
Sign=(cosd (theta)/abs (cosd (theta)))
U=.8
R=12
C=5
a=[1 0 1 0 0 0 0 0 0 0 0; 0 1 0 1 0 0 0 0 0 0 0; 0 0 (-R*sind (theta)) (R*cosd (theta)) 0 0 0 0 0 0 1; 0 0 0 0 1 0 1 0 0 0 0; 0 0 0 0 0 1 0 1 0 0 0; 0 0 0 0 (-R*sind (theta)) (R*cosd (theta)) 0 0 0 0 0; 0 0 -1 0 -1 0 0 0 (4*abs (sign)) 0 0; 0 0 0 -1 0 -1 0 0 (-4*u*sign) 0 0; 0 0 -c (3*R) -c (-3*R) 0 0 (-4*(y-c)) 0 0; 0 0 0 0 0 0 0 0 (-u*sign) 1 0]
b=[Ax; Ay; Bx; By;Cx; Cy; Dx; Dy; NB; Nc; T]
a+b=
4 个评论
Azzi Abdelmalek
2016-6-12
What kind of trouble?
Emily Gobreski
2016-6-12
Roger Stafford
2016-6-12
If the quantities Ax, Ay, Bx, etc. are each scalar numbers, the most serious problem you have is that the two arrays you are attempting to add have different sizes. The ‘a’ array is of size 10-by-11 and the ‘b’ array would be of size 11-by-1. You need to figure your way out of that problem - what are you adding to what? If you do repmat(b,1,10).’, then you could add them (note the transpose operator.) Instead of that you could use the ‘bsxfun’ along with a transpose.
Emily Gobreski
2016-6-12
采纳的回答
Star Strider
2016-6-12
MATLAB is case-sensitive, so sign~=Sign and so for the rest. I corrected as many of those as I could find. We also don’t have ‘y’:
a=[1 0 1 0 0 0 0 0 0 0 0; 0 1 0 1 0 0 0 0 0 0 0; 0 0 (-R*sind (theta)) (R*cosd (theta)) 0 0 0 0 0 0 1; 0 0 0 0 1 0 1 0 0 0 0; 0 0 0 0 0 1 0 1 0 0 0; 0 0 0 0 (-R*sind (theta)) (R*cosd (theta)) 0 0 0 0 0; 0 0 -1 0 -1 0 0 0 (4*abs ( Sign)) 0 0; 0 0 0 -1 0 -1 0 0 (-4*U*Sign) 0 0; 0 0 -C (3*R) -C (-3*R) 0 0 (-4*(y-C)) 0 0; 0 0 0 0 0 0 0 0 (-U*Sign) 1 0];
Supply ‘y’ and that assignment may work. I don’t know what you’re doing with ‘b’, and we don’t have any of its elements, so I don’t know if you can do the addition.
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