how to test for palindrome of the product of unknown digit numbers

1 次查看（过去 30 天）

OLUBUKOLA ogunsola 2016-6-14

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/289903-how-to-test-for-palindrome-of-the-product-of-unknown-digit-numbers

评论： OLUBUKOLA ogunsola 2016-6-16

when testing out palindromic numbers for three digit numbers , we could create the products of the three digits this way:

 for i=999:-1:100
    for j=999:-1:100
    answer = i*j;

what if we do not know the number of digit and the number of digit will be the input to the code , how can i adjust the 'for loop' to cater for the unknown number of digits?

say input could be 2 digits or 4 digits or 5 digits and the code will create the products

thanks

采纳的回答

Walter Roberson 2016-6-14

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/289903-how-to-test-for-palindrome-of-the-product-of-unknown-digit-numbers#answer_225515

在 MATLAB Online 中打开

for j = 10^(number_of_digits) - 1 : -1 : 10^(number_of_digits-1)

5 个评论
显示 3更早的评论隐藏 3更早的评论

Walter Roberson 2016-6-15

I do not see anywhere in your code where your store anything into a matrix.

I tested my code from number_of_digits = 1 to number_of_digits = 4 and it works fine.

OLUBUKOLA ogunsola 2016-6-15

@Walter Roberson looking closely at for j = 10^(number_of_digits) - 1 : -1 : 10^(number_of_digits-1) that you earlier suggested actually works, the problem i had earlier with it was placement of the numerous (-1).thanks

请先登录，再进行评论。

更多回答（1 个）

Image Analyst 2016-6-15

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/289903-how-to-test-for-palindrome-of-the-product-of-unknown-digit-numbers#answer_225539

在 MATLAB Online 中打开

Try this:

% Code with a palindrome.
theNumber = 123848321; % A palindrome
str = sprintf('%d', theNumber)
if all(str == fliplr(str))
  message = sprintf('%d is a palindrome', theNumber);
  uiwait(helpdlg(message));
else
  message = sprintf('%d is NOT a palindrome', theNumber);
  uiwait(helpdlg(message));
end
% Code with a non-palindrome.
theNumber = 163848321; % NOT a palindrome
str = sprintf('%d', theNumber)
if all(str == fliplr(str))
  message = sprintf('%d is a palindrome', theNumber);
  uiwait(helpdlg(message));
else
  message = sprintf('%d is NOT a palindrome', theNumber);
  uiwait(helpdlg(message));
end