Can someone do this calculation without for loops ?
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a = [1 2 3; 4 5 6];
b = [ 1 2 3];
for n = 1: size(a,1)
for m = 1:size(a,2)
k(n,m,:)= b.*b*a(n,m)
end
end
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Azzi Abdelmalek
2016-6-15
编辑:Azzi Abdelmalek
2016-6-15
a = [1 2 3; 4 5 6];
b = [ 1 2 3];
bb=reshape(b.*b,1,1,[])
out=bsxfun(@times,a,bb)
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