Checking Cell Array for positive numbers

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I have a (:,1) array which should be in a range of 0>ArrayValues>-150. What would I use to check to see if any are out of the range, and then list how many are out of the range. I have tried sum(), and Array<0.
  2 个评论
Thorsten
Thorsten 2016-6-21
It would be helpful to upload your data, or at least a minimal version that reproduces the errors you describe below.
Stephen23
Stephen23 2016-6-21
编辑:Stephen23 2016-6-21
@Tessa Aus: Is there a particular reason why the data in a cell array? This whole task would be trivially easy if the data were stored in a much simpler numeric array.

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Star Strider
Star Strider 2016-6-16
编辑:Star Strider 2016-6-16
Try this:
ArrayValues = randi([-200, 50], 1, 100); % Create Data
OutOfRange = (ArrayValues > -150) & (ArrayValues < 0); % Logical Vector, Use ‘find’ To Get Indices
NrOutOfRange = sum(OutOfRange);
EDIT If ‘ArrayValues’ is a cell array, this works:
ArrayValues = {randi([-200, 50], 1, 100)}; % Create Data
OutOfRange = cellfun(@(x) (x > -150) & (x < 0), ArrayValues, 'Uni',0); % Use ‘cellfun’
NrOutOfRange = sum(OutOfRange{:}); % Change To Address Cell Array
  6 个评论
Tessa Aus
Tessa Aus 2016-6-21
So I deleted the first cell because it contained the only letters in the cell array. And reran the system and the exact same error showed up. So it looks as though the error is stemming from something other then the letters (which are not gone) and 'uni'. Any final thoughts before I try a different method? The values are for example -112.365 or -105.09. Thanks
Star Strider
Star Strider 2016-6-21
I don’t have either your data or a clear idea of what you want to do, so I have no further thoughts.
You can remove the ‘'Uni',0’ if you want, although I seriously doubt it’s the problem.

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更多回答(1 个)

Azzi Abdelmalek
Azzi Abdelmalek 2016-6-16
idx=a(:,1)>-150 & a(:,1)<0
out=sum(~idx)
  1 个评论
Tessa Aus
Tessa Aus 2016-6-16
I get an error "Undefined operator '>' for input arguments of type 'cell'. This is the error I keep getting whenever I use this signage.

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