Checking Cell Array for positive numbers
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I have a (:,1) array which should be in a range of 0>ArrayValues>-150. What would I use to check to see if any are out of the range, and then list how many are out of the range. I have tried sum(), and Array<0.
2 个评论
Thorsten
2016-6-21
It would be helpful to upload your data, or at least a minimal version that reproduces the errors you describe below.
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Star Strider
2016-6-16
编辑：Star Strider
2016-6-16
Try this:
ArrayValues = randi([-200, 50], 1, 100); % Create Data
OutOfRange = (ArrayValues > -150) & (ArrayValues < 0); % Logical Vector, Use ‘find’ To Get Indices
NrOutOfRange = sum(OutOfRange);
EDIT — If ‘ArrayValues’ is a cell array, this works:
ArrayValues = {randi([-200, 50], 1, 100)}; % Create Data
OutOfRange = cellfun(@(x) (x > -150) & (x < 0), ArrayValues, 'Uni',0); % Use ‘cellfun’
NrOutOfRange = sum(OutOfRange{:}); % Change To Address Cell Array
6 个评论
Tessa Aus
2016-6-17
Star Strider
2016-6-17
My code in both the initial and edited code (edited to accommodate the cell vector) runs without error in R2016a.
I cannot reproduce the error you’re getting.
I don’t know the reason it doesn’t work with your code because I don’t have your code.
Tessa Aus
2016-6-17
Star Strider
2016-6-17
The ‘'Uni',0’ is shorthand for ‘'UniformOutput',false’.
From the documentation for cellfun, that option:
- Requests that the cellfun function combine the outputs into cell arrays A1,...,Am. The outputs of function func can be of any size or type.
I’m not sure how to advise you with respect to processing your ‘cell array with numbers and letters’. This is new information that I would have preferred you’d mentioned at the outset, preferably with some sample data and how you want to handle the numbers and letters.
Tessa Aus
2016-6-21
Star Strider
2016-6-21
I don’t have either your data or a clear idea of what you want to do, so I have no further thoughts.
You can remove the ‘'Uni',0’ if you want, although I seriously doubt it’s the problem.
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