How to solve matrix as a function

1 次查看（过去 30 天）
Josh
Josh 2012-2-15
I know this is simple for some, but I need a hand. I am learning this as I go with no assistance.
If I have three known variables, or 3x1 matrix Theta. I know m=cosd(Theta), and n=sind(Theta), and I want to solve another matrix T for each of the three Theta, how would you code this?
Ex: T = [m^2,n^2,2mn; n^2,m^2,-2mn; m,n,m^2n^2]
How can I enter this in and get three separate T matrices as my output? Thanks!

请先登录，再回答此问题。

回答（3 个）

Benjamin Schwabe
Benjamin Schwabe 2012-2-15
What does m^2 mean? It's a vecor, isn't it? Componentwise operation? Or is it a real vecor-vectormultiplication resulting in a single number?
  1 个评论
Josh
Josh 2012-2-15
m^2 is m squared, which will be a number in row1, column1. Likewise, n^2 is in row 1, column2, and so on. m=cosd(Theta). I am just trying to find the code where I can solve for all Thetas at once.

请先登录，再进行评论。

Walter Roberson
Walter Roberson 2012-2-15
Andrei Bobrov
Andrei Bobrov 2012-2-15
m = reshape(cosd(Theta),1,1,[])
mq = m.^2;
nq = 1 - mq;
n = sqrt(nq);
mn = 2*m.*n;
T = [mq, nq, mn; nq,mq,-mn; m,n,mq.*nq]

类别

在 Help Center 和 File Exchange 中查找有关 Mathematics and Optimization 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by