finding a string in a cell array

ids1='519448(EPS1MN)' '519448(EPS2MN)' '519448(EPS3MN)' '519448(EPS4MN)' '519448(EPS5MN)' '519448(LTMD)' '519448(P)' '519448(DPS)' '519448(EPS)'
I want to find the cell that has embedded in it EPS1MN ,....EPS5MN
writing the following codes:
x2a=find(~isempty(strfind(ids1,'EPS1MN'))); % select rows.
x2b=find(~isempty(strfind(ids1,'EPS2MN')));
x2c=find(~isempty(strfind(ids1,'EPS3MN')));
x2d=find(~isempty(strfind(ids1,'EPS4MN')));
x2e=find(~isempty(strfind(ids1,'EPS5MN')));
is returning a value of 1 for x2a...x2e which is obviously wrong since the answers should be 1,2,...5
I am wondering what went wrong?

2 个评论

wesso commented
the two answers work well with EPS1...EPS5 but they fail to identify the cell when the cell is (P). (i.e I want the answer to identify cell '519448(P)' and gets an answer of 7. Any help with this?
If we give you the solution with (P), you will ask again it's not working with (T) or another string!

请先登录,再进行评论。

 采纳的回答

ids1={'519448(EPS1MN)'
'519448(EPS2MN)'
'519448(EPS3MN)'
'519448(EPS4MN)'
'519448(EPS5MN)'
'519448(LTMD)'
'519448(P)'
'519448(DPS)'
'519448(EPS)'}
out=find(~cellfun(@isempty,regexp(ids1,'EPS[12345]MN')))

更多回答(1 个)

类别

帮助中心File Exchange 中查找有关 Characters and Strings 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by