finding a string in a cell array
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ids1='519448(EPS1MN)' '519448(EPS2MN)' '519448(EPS3MN)' '519448(EPS4MN)' '519448(EPS5MN)' '519448(LTMD)' '519448(P)' '519448(DPS)' '519448(EPS)'
I want to find the cell that has embedded in it EPS1MN ,....EPS5MN
writing the following codes:
x2a=find(~isempty(strfind(ids1,'EPS1MN'))); % select rows.
x2b=find(~isempty(strfind(ids1,'EPS2MN')));
x2c=find(~isempty(strfind(ids1,'EPS3MN')));
x2d=find(~isempty(strfind(ids1,'EPS4MN')));
x2e=find(~isempty(strfind(ids1,'EPS5MN')));
is returning a value of 1 for x2a...x2e which is obviously wrong since the answers should be 1,2,...5
I am wondering what went wrong?
2 个评论
Azzi Abdelmalek
2016-6-22
wesso commented
the two answers work well with EPS1...EPS5 but they fail to identify the cell when the cell is (P). (i.e I want the answer to identify cell '519448(P)' and gets an answer of 7. Any help with this?
Azzi Abdelmalek
2016-6-22
If we give you the solution with (P), you will ask again it's not working with (T) or another string!
采纳的回答
Azzi Abdelmalek
2016-6-22
ids1={'519448(EPS1MN)'
'519448(EPS2MN)'
'519448(EPS3MN)'
'519448(EPS4MN)'
'519448(EPS5MN)'
'519448(LTMD)'
'519448(P)'
'519448(DPS)'
'519448(EPS)'}
out=find(~cellfun(@isempty,regexp(ids1,'EPS[12345]MN')))
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