Running an Iteration for single variable.

Question

Alex 2012-2-15

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/29195-running-an-iteration-for-single-variable

Hey all, I've been using a closure loop with fsolve to crunch data. The below code took 3 rows of data from a .csv, and plugged it into 3 equations for simultaneous solution. I would like to modify the code to solve a single equations with a single variable, a function that fsolve is not required for. I still need to iterate, because I have to solve this equation many times sequentially, and they still need to output to a .csv. How would you go about it?

data = csvread('data.csv');
assert (mod(size(data, 1), 2) == 0, ...
      'Input data must have an integer multiple of 2 rows');
assert (size(data, 2) == 6, ...
      'Input data must have exactly six columns.');
nsys = size(data, 1) / 2;
soln = zeros(nsys, 2);
options=optimset('MaxFunEvals',1e10,'MaxIter',25000);
for k = 1 : nsys,
  F = generate_system(data(2*(k-1) + (1:2), 1:end));
  guess = [3 3];
  soln(k, :) = fsolve(F, guess,options);
end
fid=fopen('results.csv','w');
fprintf(fid,'%5.5f %5.5f\n',soln);
fclose(fid);

generate_system looks like this:

function F = generate_system(p)
  assert (ndims(p) ==2, ...
          'System parameters ''p'' must be 2D matrix.');
    assert (all(size(p) ==[2,6]), ...
            'System parameters must be 2-by-6 matrix.');
    y = p(:,1);
    n = p(:,2);
    k = p(:,3);
    n0 = p(:,4);
    k0 = p(:,5);
    R = p(:,6);
      F = @(x) ((((n0-(n-1i.*k))./(n0+(n-1i.*k)))+(((n-1i.*k)-(x(1)-1i.*x(2)))./((n-1i.*k)+(x(1)-1i.*x(2)))).*(exp(-2.*1i.*(2.*pi./y).*(n-1i.*k).*300)))./(1+((n0-(n-1i.*k))./(n0+(n-1i.*k))).*(((n-1i.*k)-(x(1)-1i.*x(2)))./((n-1i.*k)+(x(1)-1i.*x(2)))).*(exp(-2.*1i.*(2.*pi./y).*(n-1i.*k).*300))))-R;
end