Please help me in generating a matrix of ones for a given matrix

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MANISH KUMAR
MANISH KUMAR 2016-6-30
编辑： Stephen23 2016-7-6
Suppose if I already have a matrix 'X' having only one '1' in each row for example matrix given below
X = [0 0 0 0 1 0 0 0 0 0;
0 1 0 0 0 0 0 0 0 0;
0 0 1 0 0 0 0 0 0 0;
1 0 0 0 0 0 0 0 0 0;
0 0 0 0 0 1 0 0 0 0]
i need a matrix a few (specified number) '1's after existing '1' in each row for example output matrix is
Y = [0 0 0 0 1 1 1 1 0 0;
0 1 1 1 1 1 0 0 0 0;
0 0 1 1 1 0 0 0 0 0;
1 1 0 0 0 0 0 0 0 0;
0 0 0 0 0 1 1 1 1 0]
code for matrix 'X'is
P = 5; % The number of competitive projects
T = 10; % The number of time periods
D = [4; 5; 3; 2; 4];
excludedcount = D-1;
X = zeros(P,T);
for row = 1:P
rv = [1, zeros(1, T - excludedcount(row) - 1)];
X(row, 1 : (T - excludedcount(row))) = rv(randperm(numel(rv)));
end

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dpb
dpb 2016-6-30
"Dead-ahead" solution is simply
D = [4; 5; 3; 2; 4];
for row = 1:P
ic=find(X(row,:); % the '1' column index
X(row,ic:ic+D-1)=ones(1,D); % insert the ones vector at that location
end
With some thought this could undoubtedly be transformed to use arrayfun and the multiple outputs from find on the array w/o the explicit loop; whether that would be any faster is questionable I'd venture...
  1 个评论
MANISH KUMAR
MANISH KUMAR 2016-7-6
if any row contains zeros only then it shows error in this line
X(row,ic:ic+D(row)-1)=ones(1,D(row));
For example matrix is
Y =
0 1 0 0 0 0 0 0 0 0
0 0 0 1 0 0 0 0 0 0
0 0 0 0 0 0 1 0 0 0
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
in this matrix last two rows contains zeros only. So this code doesn't work.

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