Convert the Mathematica expression to matlab

2012 2 16
1 个回答
回答已采纳
1 次查看（30 天）

0 个投票

Hello I want to convert the following lines to matlab.But I am unable to do it with matlab to function.Please help..
x[i_]:=x[i]=x[i-1]+h f1[t[i-1],x[i-1],y[i-1],z[i-1]]+1/2 h2 (f1(1,0,0,0)[t[i-1],x[i-1],y[i-1],z[i-1]]+f1(0,1,0,0)[t[i-1],x[i-1],y[i-1],z[i-1]] f1[t[i-1],x[i-1],y[i-1],z[i-1]]+f1(0,0,1,0)[t[i-1],x[i-1],y[i-1],z[i-1]] f2[t[i-1],x[i-1],y[i-1],z[i-1]]+f1(0,0,0,1)[t[i-1],x[i-1],y[i-1],z[i-1]] f3[t[i-1],x[i-1],y[i-1],z[i-1]])
This is implementation of Taylor series.

请先登录，再回答此问题。

 采纳的回答

Thomas
Thomas 2012-2-16

0 个投票

MAtlab has inbuilt function for Taylor series
doc taylor
http://www.mathworks.com/help/toolbox/symbolic/taylor.html

2 个评论
显示 无 隐藏 无

LOKESH
LOKESH 2012-2-16
but here it is taylor method of order 3 for 3 different equations in one loop only.
Can i do that with inbuilt function.
Walter Roberson
Walter Roberson 2012-2-16
for K = 1 : length(Equations)
tans(K) = taylor(Equations(K), 3, Variables(K));
end
Looks like a single loop to me.

请先登录，再进行评论。

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 MATLAB 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by