Jacobi polynomials in MATLAB

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R shah
R shah 2016-7-5
评论: R shah 2016-7-7
i want to execute jacobi polynomials for N = j-3 where j= 0, 1,...,4, a = b = 3 and x = -0.655, the code according to my knowledge will be,
syms j
a= 3;
b=3;
for j = 0:4
display (jacobiP(j-3,3,3,-0.655))
end
but this code isn't working kindly guide me.

回答(1 个)

Karan Gill
Karan Gill 2016-7-6
Your first argument "j-3" is negative for j=0,1,2. That's what the error message says: A nonnegative integer or a symbol is expected.
If you replace "j-3" with "j" it works.
syms j
a= 3;
b=3;
for j = 0:4
jacobiP(j,3,3,-0.655)
end
ans =
1
ans =
-2.6200
ans =
3.5765
ans =
-2.8153
ans =
0.4398
  2 个评论
R shah
R shah 2016-7-6
thx sir, but i know this information i also know that jacobi polynomials are defined for n >= 0 but when we take the third derivative of jacobi polynomial we got the jacobi P(j-3, a+3, b+3, -0.655) i've taken the case when a = 0 and b = 0 so i must have to evaluate jacobiP(j-3, 3,3,-0.655). should i consider the values:
0 for j = 0
0 for j = 1
0 for j = 2
-2.,815 for j = 3
0.4398 for j = 4
R shah
R shah 2016-7-7
whats wrong if i take this code for above problem
clc; clear all
syms j
a = 3 ;
b = 3 ;
for j = 0:4
if j-3 == -3:-1
display(jacobiP(j-3,3,3,0.655) == 0)
else
display(jacobiP(j-3,3,3,0.655))
end
end

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