help in this plz

Question

Nasir Qazi 2012-2-19

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/29575-help-in-this-plz

I have Values like this

C2 = 0.10;
C3 = 0.10;
C4 = 0.20;
C5 = 0.20;
C6 = 0.20;
P1=190;
P2=72.2;
P3=51.6;
P4=20.44;
P5=15.57;
P6= 4.956;
K1=P1/P;
K2=P2/P;
K3=P3/P;
K4=P4/P;
K5=P5/P;
K6=P6/P;

note :- this is very lengthy and I want to make it shorter and calculating like this

for c = [0.20,0.10,0.10,0.20,0.20,0.20]
  for P = [190,72.2,51.6,20.44,15.57,4.956] 
      PG = 50;
     K = (P/PG);
     A = c*(K-1);
     B = c*(K-1)/K;
     nv = A/(A-B);
     disp(nv)
  end  
end

Can I use these code to calculate it in a simpler way or I am need to change the code , suggest plz

thanks

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Image Analyst 2012-2-19

Inside your loop, the c's cancel out in the nv division, so nv, K, and PG don't depend on c at all so why are they in a loop over c? Also, in the first chunk of code, I assume P1 = P(1), so what is P? You can't do K(1) = P(1) ./ P because the dimensions don't match so I have no idea what you want to do.

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Answer 1

Walter Roberson 2012-2-19

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Yes, you can use loops such as you show. Your "for" syntax is valid.

You might want to store the answers after you calculate them, though.

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Walter Roberson 2012-2-19

Unfortunately I do not have access to a MATLAB license on weekends.

Jan 2012-2-19

The code runs fine and "nv" is calculated - but only the last value is stored. Because "nv" does not depend on "c" at all, the outer loop can be omitted.

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