Assign vector to vector with gaps

2 次查看（过去 30 天）
baxbear
baxbear 2016-7-16
评论： baxbear 2016-7-22
Stuff doesn't matter - was tired - start reading at Edit1 - sry
Hello,
I have a matrix of row size m and a matrix of row size n where m > n and x = m - n. I also got a vector k of length x with different row indices of m. Now I want to assign n to m by not touching entries m(k) important is that these rows stay unchanged and in place.
Is there an easy one-liner? like:
m(m ~= x) = n;
or
m(m ~= m(x)) = n;
but seems not to work :(
Hope you can help me.
Thanks in advance.
=================================================================
HERE!:-> @Edit1: Oh, uff was late yesterday and yeah what ever I wrote there is pretty confusing and wrong... so again:
Matrix A of size m * _ where m is the number of rows and matrix B of size n * _ where n is the number of rows. Still true is: m > n and x = m - n and V is a vector with x rows.
Example:
A = [1,1,1; 2,2,1; 3,3,4; 8,3,6; 8,3,0; 8,6,3];
B = [4,2,5; 4,3,2; 6,3,2; 8,0,9];
V = [2; 4];
Result in A:
A = [4,2,5; 2,2,1; 4,3,2; 8,3,6; 6,3,2; 8,0,9];
just for much bigger matrices. Sorry for my unclear post yesterday hope you are still willing to help me.
  2 个评论
Azzi Abdelmalek
Azzi Abdelmalek 2016-7-16
You can make your question clear by posting an example
Image Analyst
Image Analyst 2016-7-16
编辑：Image Analyst 2016-7-16
Your terminology is pretty sloppy. Are m and n the width of the matrix (number of columns which is the "row size" or "row length") or the names of the matrices? Are your matrices really column vectors? Or row vectors?
This is what I have so far but can't go further because of ambiguities in your terminology.
m=10
n=6
x = m-n
vec1 = randi(99, 1, m) % First "matrix" (sample data)
vec2 = randi(99, 1, n) % Second "matrix" (sample data)
k = randperm(m, x) % indexes of m

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

goerk
goerk 2016-7-19
A = [1,1,1; 2,2,1; 3,3,4; 8,3,6; 8,3,0; 8,6,3];
B = [4,2,5; 4,3,2; 6,3,2; 8,0,9];
V = [2; 4];
% create 'inversion' of V (there may be better ways)
notV = 1:size(A,1); % vector from 1 to number of rows
notV(V) = []; % delete rows which are in V
% over write the rows that are not in V
A(notV,:)=B
  3 个评论
显示 1更早的评论
goerk
goerk 2016-7-19
Thanks, that's a nice short solution.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by