0 个投票

I can't figure out what this bit of code is doing:
[m,n]=find(min(a))
I know that it is not returning the indices of the minimum entries in the array 'a', but what is it doing?

请先登录，再回答此问题。

 采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2016-7-17
编辑：Azzi Abdelmalek 2016-7-17

0 个投票

[m,n]=min(a)
m is the minimum, n is the index of n m in a
You can try an example
a=[4 7 3 6 2 7 8]
[m,n]=min(a)
Now if you write
r=find(min(a))
you will find the result
r=1
because in our example min(a)=2, it contains just one elment, so there is one index=1

更多回答（1 个）

Walter Roberson
Walter Roberson 2016-7-17

0 个投票

If a is a 2D or more array, then min(a) would return the minimum along the first dimension. Some of those minima might be negative, some might be positive, some might be 0. find() applied to that is going to return the indices of the non-zero elements within that minima. For example if a is 2D array then [m,n]=find(min(a)) is going to return the indices of the columns where the minima is non-zero.

类别

在 帮助中心 和 File Exchange 中查找有关 Operators and Elementary Operations 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by