Radio button to ON-OFF figure visibility

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Hello All, I have been working on GUI. Now I am stuck with one requirement, which is to have a radio button to ON-OFF the image visibility. I have the "Calculate" push button which will calculate in user defined loops where I have 3 images per loop. Every time the script runs the image pops up. If the loops are huge in number the calculation process takes more time. So I want to have a radio button so that when selected the images will popup meaning visibility will be ON while unselected, the figures will not pop up so the user can minimize the GUI and work on something else till a message pops up as calculation is completed. I take user defined location to save the images so user will get to the images whenever he wants.
I tried with figure('Visible','off') and it worked well so I just want to add it with a radio button to give user the choice to ON-OFF images.
  10 个评论
Adam
Adam 2016-7-20
Are you using a radio button or a checkbox? Your question talks about a radiobutton, but your code since then suggests you are using a checkbox.
adi kul
adi kul 2016-7-20
I previously tried with checkbox, but could not make it work so someone suggested to make it radio button hence name is still checkbox but the button is radiobutton.

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采纳的回答

adi kul
adi kul 2016-7-20
Thank you all for your help. I managed to Solve it using
if get(handles.checkbox2, 'Value')
Visibility = 'on';
else
Visibility = 'off';
end
figure('Visible', Visibility)

更多回答(1 个)

Adam
Adam 2016-7-19
编辑:Adam 2016-7-19
Right click on your radio button group panel (you should put radio buttons in a button panel if they aren't already) and select the SelectionChangedCallback if you are in GUIDE. This will create the function for you then you simply code it as e.g.
set( myFig, 'Visible', hObject.String )
for some figure if you name the options on the radio buttons as 'On' and 'Off'

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