Decrease the least and increase the highest
显示 更早的评论
I have an array
A = [1 -3 -6 10 2 3 7 -1 -9 -3]
B = [1 2 3 4 5 6 7 8 9 10]
1) I want to check the least negative and the highest positive in array A.
2) In the corresponding number in Matrix B, if it is the least negative then multiply the number in B by 10 and if it is the highest positive, then multiply the number in B by 100.
3) Then B = [1 2 3 400 5 6 7 8 90 10]
2 个评论
Image Analyst
2016-7-21
Are you sure that's what they want? It's kind of ambiguous. You could also assert that the least negative value is the -1, and the most negative value is -9, in which case the 8 would be multiplied by 10 instead of the 9.
Star Strider
2016-7-21
OP seems to be posting homework problems.
采纳的回答
Star Strider
2016-7-21
A = [1 -3 -6 10 2 3 7 -1 -9 -3];
B = [1 2 3 4 5 6 7 8 9 10];
[~,idxlo] = min(A);
[~,idxhi] = max(A);
B(idxlo) = 10*B(idxlo);
B(idxhi) = 100*B(idxhi)
B =
1 2 3 400 5 6 7 8 90 10
更多回答（1 个）
B(A == max(A)) = B(A == max(A))*100;
B(A == min(A)) = B(A == min(A))*10;
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