Subscripted assignment dimension mismatch in structure.

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purdueaviator 2016-7-23

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回答： Div Tiwari 2016-8-8

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I am trying to create a structure with a lot of information and multiple layers.

Level(10).Sublevel(5).XXXXX = 'test' works just fine

However, when I try to add another sublevel such as

Level(10).Sublevel(5).Subsublevel(15).XXXXX = 'test'

I get the Subscripted assignment dimension mismatch error.

Is this a MATLAB limitation or am I doing something wrong?

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Geoff Hayes 2016-7-23

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At what point do you call the second line of code? If I execute the following two lines in succession

 Level(10).Sublevel(5).XXXXX = 'test';
 Level(10).Sublevel(5).Subsublevel(15).XXXXX = 'test';

then I don't observe any errors. Please provide more details.

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Answer 1

Div Tiwari 2016-8-8

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Was the first assignment Level(10).Sublevel(5).Subsublevel = 'test'? That makes 'Level(10).Sublevel(5).Subsublevel' a 'char' vector of length 4. As a result, indexing into 'Subsublevel' with an index greater than 4 gives a 'Field assignment to a non-structure array object' error. Using an index of 4 or less will result in a size mismatch error.

To get around this, you may reassign 'Subsublevel' as a struct before the second assignment, as follows:

>> Level(10).Sublevel(5).Subsublevel = 'test';

>> Level(10).Sublevel(5).Subsublevel = struct;

>> Level(10).Sublevel(5).Subsublevel(15).XXXXX = 'test';