How to take the X smaller values of an array ?

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Hidir ABAY
Hidir ABAY 2016-7-27
回答： Paxorus Sahay 2016-7-27
Hello everyone,
I have an array x (for example size(x)= 1, 10) and x=(1, 4, 100, 3, 14, 56, 8, 90, 23, 2).
My question is how can I keep the 6 smaller values of x without making a sort ? Because when I do a sort, it changes the place of the values.
For example if y is the output array I want that y=(1, 4, 3, 14, 8, 2)
Thanks for reading.

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采纳的回答

Adam
Adam 2016-7-27
编辑：Adam 2016-7-27
[y,idx] = sort( x );
[~,idx2] = sort( idx(1:6) );
y = y( idx2 );
There may be a slightly more elegant way, but that does the job.

更多回答（1 个）

Paxorus Sahay
Paxorus Sahay 2016-7-27
This sliding insertion technique might be what you're looking for.
function [minima] = smallest(vec, n)
minima = vec(1:n);
[maxElem, idx] = findMax(minima);
for i = (n+1):length(vec)
if vec(i) < maxElem
minima(idx:end) = [minima(idx+1:end) vec(i)];
[maxElem, idx] = findMax(minima);
end
end
end
function [maxElem, firstIndex] = findMax(vec)
% assuming vec not empty
maxElem = max(vec);
allMatches = find(vec == max(vec));
firstIndex = allMatches(1);
end
Example usage:
x = [1, 4, 100, 3, 14, 56, 8, 90, 23, 2];
y = smallest(x, 6);

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