Attempted to access x(5); index out of bounds because numel(x)=4.

Question

lotus whit 2016-8-2

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/298142-attempted-to-access-x-5-index-out-of-bounds-because-numel-x-4

评论： Image Analyst 2016-8-2

could you please to help me , i have this error when i tried to run this code which calculate distance between two points groups

    x = [2,3,4,5];
y = [4,4,5,4];
s_x = size(x);
d2 = (s_x(1,2));
d = zeros(1,4)
for ii=1:1:d2
    d(ii) = sqrt((x(ii+1)-x(ii))^2+(y(ii+1)-y(ii))^2);
    end
 any one have any idea about solution?

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Image Analyst 2016-8-2

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/298142-attempted-to-access-x-5-index-out-of-bounds-because-numel-x-4#answer_230574

在 MATLAB Online 中打开

It looks like you're trying to do this:

x = [2,3,4,5];
y = [4,4,5,4];
deltax = diff(x)
deltay = diff(y)
distances = sqrt(deltax .^2 + deltay .^2)

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

Answer 2

James Tursa 2016-8-2

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/298142-attempted-to-access-x-5-index-out-of-bounds-because-numel-x-4#answer_230573

编辑：James Tursa 2016-8-2

The error is caused by ii iterating from 1 to 4, but you use ii+1 (=5 at last iteration) as an index into the x and y vectors which are only of length 4. For your example, what would you like the desired output to be? I.e., what would the desired values of d be for your example?

2 个评论
显示无隐藏无

lotus whit 2016-8-2

Thank you about your fast response, i want to calculate the distance between each point in x,y vectors , for example point1(x1,y1) , point2(x2,y2), i need to calculate the distance between point1 and point2 then calculate distance point2 and point3 then point3 and point4 and so on dependent on length of vector(x) and vector(y). thank you again