Replacing NaN with its succeeding values

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Sowmya MR
Sowmya MR 2016-8-2
回答： Andrei Bobrov 2016-8-2
I have an array which should replace the NaN with its succeeding value. For example:
A=[NaN NaN 1 1 0 0 NaN 0 NaN 1 1]
then output should be
B=[1 1 1 1 0 0 0 0 1 1 1].
Can someone please help me with this?

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采纳的回答

Brendan Hamm
Brendan Hamm 2016-8-2
This is simply a 1-dimensional interpolation using the next method with extrapolation:
A=[NaN NaN 1 1 0 0 NaN 0 NaN 1 1]
x = 1:length(A); % Create a vector of indices
idx = ~isnan(A); % Find the locations of valid data
% Use the good data to interpolate on all the locations in x.
B = interp1(x(idx),A(idx),x,'next','extrap')

更多回答（1 个）

Andrei Bobrov
Andrei Bobrov 2016-8-2
A=[NaN NaN 1 1 0 0 NaN 0 NaN 1 1];
z = flip(A(:));
x = ~isnan(z);
z = z(x);
B = flip(z(cumsum(x)))';

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