I want to do element comparison between two matrices

2016 8 2
1 个回答
回答已采纳
更新时间：2016 8 2
28 次查看（30 天）

0 个投票

I want to do element comparison between two matrices and if the second element is less than or equal to the previous one it should return that element as result of that matrix...for example 1 st matrix A=[1 2 3 4 5 6]; second Matrix B=[0.1 1 1.5 4.5 4 2.5 2 4]; every element of B has to be checked with A which is in ascending order and when the element of is < or = element of A that should return that value or else should go to check for next element. As a result it shall produce Result=[1 1 2 5 4 3 2 4]. I tried writing with for loop I get error dimension of two input matrix must match which is not in my case. Please help me out. TIA!

1 个评论
显示 -1更早的评论 隐藏 -1更早的评论

Hems
Hems 2016-8-2
编辑：Azzi Abdelmalek 2016-8-2
A=[1 2 3 4 5 6];
B=[0.1 1 1.5 4.5 4 2.5 2 4];
for i=1:max(size(B))
for j=1:max(size(A)-1)
if B(1,i)<=A(1,j)
R(1,i)=A(1,j);
break
else
R(1,i)=A(1,j+1);
end
end
end
It works !!! but is there way to make it very fast I have more than a million elements to compare.

请先登录，再进行评论。

请先登录，再回答此问题。

 采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2016-8-2

1 个投票

A=[1 2 3 4 5 6];
B=[0.1 1 1.5 4.5 4 2.5 2 4]
BB=permute(B,[1 3 2])
C=bsxfun(@ge ,A,BB)
for k=1:numel(B)
out(k)=A(find(C(:,:,k),1))
end

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Matrices and Arrays 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by