Compare column vector to matrix
1 次查看(过去 30 天)
显示 更早的评论
Hello,
I'm trying to find the first element and its index into a 73X615 matrix, where each value should be less or equal to a value in 73X1 column vector. So let's say that the matrix is
B = -5 + (5+1)*rand(73,615);
and the vector is
A = -5 + (5+1)*rand(73,1)
My intention is to extract a columns vectors [C, iC], where each value of C is the first value in B that is less or equal than the value in A at the corresponding row, and iC is the index of that value.
My apologies if the question seems a bit contrived, but I'm new to Matlab and I didn't know how to formulate it more clearly.
I hope you can help me with this issue, before hand, many thanks.
0 个评论
采纳的回答
Azzi Abdelmalek
2016-8-5
编辑:Azzi Abdelmalek
2016-8-5
B = -5 + (5+1)*rand(73,615)
A = -5 + (5+1)*rand(73,1)
id=bsxfun(@le,B,A)
for k=1:size(id,1)
ii=find(id(k,:),1)
out(k,1:2)=[B(k,ii) ii]
end
Incase there are empty indices
B = -5 + (5+1)*rand(73,615)
A = -5 + (5+1)*rand(73,1)
id=bsxfun(@le,B,A)
kk=0
for k=1:size(id,1)
ii=find(id(k,:),1)
if ~isempty(ii)
kk=kk+1
out(kk,1:2)=[B(k,ii) ii]
end
end
out
7 个评论
Azzi Abdelmalek
2016-8-5
Simon, this is not how it works in this forum, when an answer satisfies your need, you have to mark the answer as accepted. You can also ask for some explanations related to your question, if it's not you have to post another question.
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!