Don't use carMatrix. Just index. And the answers to your questions follow the fixed code where you create the structure array. See below:
Car.id = '';
Car.mileage = 0;
Car.model = '';
Car.maxSpeed = 0;
carMatrix=[];
for i = 1:3
Car(i).id = strcat('A',num2str(i));
Car(i).mileage = 15 + i;
Car(i).model = strcat('XYZ',num2str(i));
Car(i).maxSpeed = 100 + 10*i;
end
% 1) Find maximum and minimum value of the 'mileage' field of all the Car in carMatrix.
% 2) Find Car object having maximum and minimum value of mileage
% 3) Find average 'mileage' (i.e. (Car1.mileage + Car2.mileage + Car3.mileage) / 3)
allMileages = [Car.mileage] % Strings all mileages together into one vector for convenience.
[maxMileage, indexOfMaxCar] = max(allMileages)
[minMileage, indexOfMinCar] = min(allMileages)
averageMileage = mean(allMileages)
% 4) Suppose in some scenario I have following data Car2.mileage = 18 and Car3.mileage = 18.
% So if I want to find out all the Car objects whose mileage is 18,
Car(2).mileage = 18;
Car(3).mileage = 18;
allMileages = [Car.mileage]
mileageIs18 = find(allMileages == 18)
% then it should return Car2 and Car3 along with their rownumber.
for k = mileageIs18
Car(k) % Echo to command window
end
