Hi. I've written this code to plot the graph it produces. However, the top three lines have complex parts to them. How can I plot only the real parts? Code follows:
%Matlab code for "MATLAB
%Question 1
%
%13/02/12
function [lmda, Ct] = problem
%QUESTION 1%
rs=0.05; %rotor solidity
Cl=2*pi; %specific lift coefficient
pa1=0.1745329250; %pitch angle 1
pa2=0.0872664625; %pitch angle 2
pa3=-0.0017453292; %pitch angle 3
pa4=-0.0349065850; %pitch angle 4
pa5=-0.0872664625; %pitch angle 5
%--------------------%
i=1;
for lmda=0:0.1:20;
a2(i)=(((((rs*lmda*Cl)/16)+0.5)^2)-((rs*lmda*Cl*(1-(lmda*pa1)))/8));
if a2(i) < 0
break
end
i=i+1;
end
%--------------------%
i=1;
for lmda=(0:0.1:20);
a1(i)=(((rs*lmda*Cl)/16)+0.5);
i=i+1;
end
%--------------------%
i=1;
for lmda=(0:0.1:20);
at(i)=a1(i)-sqrt(a2(i));
i=i+1;
end
%--------------------%
i=1;
for lmda=(0:0.1:20);
Ct1(i)=((rs*(lmda^2)*Cl)/2)*(((1-at(i))/lmda)-pa1);
i=i+1;
end
%----------------------------------------------------------------%
i=1;
for lmda=0:0.1:20;
a2(i)=(((((rs*lmda*Cl)/16)+0.5)^2)-((rs*lmda*Cl*(1-(lmda*pa2)))/8));
if a2(i) < 0
break
end
i=i+1;
end
%--------------------%
i=1;
for lmda=(0:0.1:20);
a1(i)=(((rs*lmda*Cl)/16)+0.5);
i=i+1;
end
%--------------------%
i=1;
for lmda=(0:0.1:20);
at(i)=a1(i)-sqrt(a2(i));
i=i+1;
end
%--------------------%
i=1;
for lmda=(0:0.1:20);
Ct2(i)=((rs*(lmda^2)*Cl)/2)*(((1-at(i))/lmda)-pa2);
i=i+1;
end
%----------------------------------------------------------------%
i=1;
for lmda=0:0.1:20;
a2(i)=(((((rs*lmda*Cl)/16)+0.5)^2)-((rs*lmda*Cl*(1-(lmda*pa3)))/8));
if a2(i) < 0
break
end
i=i+1;
end
%--------------------%
i=1;
for lmda=(0:0.1:20);
a1(i)=(((rs*lmda*Cl)/16)+0.5);
i=i+1;
end
%--------------------%
i=1;
for lmda=(0:0.1:20);
at(i)=a1(i)-sqrt(a2(i));
i=i+1;
end
%--------------------%
i=1;
for lmda=(0:0.1:20);
Ct3(i)=((rs*(lmda^2)*Cl)/2)*(((1-at(i))/lmda)-pa3);
i=i+1;
end
%----------------------------------------------------------------%
i=1;
for lmda=0:0.1:20;
a2(i)=(((((rs*lmda*Cl)/16)+0.5)^2)-((rs*lmda*Cl*(1-(lmda*pa4)))/8));
if a2(i) < 0
break
end
i=i+1;
end
%--------------------%
i=1;
for lmda=(0:0.1:20);
a1(i)=(((rs*lmda*Cl)/16)+0.5);
i=i+1;
end
%--------------------%
i=1;
for lmda=(0:0.1:20);
at(i)=a1(i)-sqrt(a2(i));
i=i+1;
end
%--------------------%
i=1;
for lmda=(0:0.1:20);
Ct4(i)=((rs*(lmda^2)*Cl)/2)*(((1-at(i))/lmda)-pa4);
i=i+1;
end
%----------------------------------------------------------------%
i=1;
for lmda=0:0.1:20;
a2(i)=(((((rs*lmda*Cl)/16)+0.5)^2)-((rs*lmda*Cl*(1-(lmda*pa5)))/8));
if a2(i) < 0
break
end
i=i+1;
end
%--------------------%
i=1;
for lmda=(0:0.1:20);
a1(i)=(((rs*lmda*Cl)/16)+0.5);
i=i+1;
end
%--------------------%
i=1;
for lmda=(0:0.1:20);
at(i)=a1(i)-sqrt(a2(i));
i=i+1;
end
%--------------------%
i=1;
for lmda=(0:0.1:20);
Ct5(i)=((rs*(lmda^2)*Cl)/2)*(((1-at(i))/lmda)-pa5);
i=i+1;
end
%----------------------------------------------------------------%
lmda=(0:0.1:20);
figure,plot(lmda,real(Ct1),'k-','Linewidth',2),grid on, hold on
plot(lmda,real(Ct2),'k--','Linewidth',2)
plot(lmda,real(Ct3),'k-.','Linewidth',2)
plot(lmda,real(Ct4),'r-','Linewidth',2)
plot(lmda,real(Ct5),'r--','Linewidth',2)
axis([0 20 0 1])
xlabel('\lambda');ylabel('C_t');title('Thrust coefficient against tip speed ratio.');
legend('\theta_T=10^{o}','\theta_T=5^{o}','\theta_T=-0.1^{o}','\theta_T=-2^{o}','\theta_T=-5^{o}');
end
%QUESTION 2%

 采纳的回答

You are plotting only the real parts. I think the problem is coming with how you're calculating these functions. You have break statements to terminate your for loops when a2 goes negative. However, the last value of a2 (the negative value) is still there.
Furthermore, you're reusing a2, but you stop calculating after a2 goes negative. This means that the rest of a2 is still there from the previous calculation. Do you really want that?
If you zoom out, so the y-axis goes higher, you will see that the function carries on doing something else. My suspicion is that this comes from calculating at based on old a2 values.
Finally, you really don't need these loops. This code is really nasty to read and debug.
lmda=0:0.1:20;
a1=(((rs*lmda*Cl)/16)+0.5);
Nice and easy. Just remember to use .* and ./ when multiplying/dividing arrays.

1 个评论

J
J 2012-2-22
Great, thank you very much! I'm new to Matlab so this style was really helpful.

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更多回答(2 个)

J
J 2012-2-22
Ok, I've tried to edit the code and get rid of loops.
rs = 0.05;
Cl = 2*pi;
pa = [10*(pi/180) 5*(pi/180) -0.1*(pi/180) -2*(pi/180) -5*(pi/180)];
lmda=1:0.1:20;
for v = 1:5
for i=1:length(lmda)
a(i) = (((rs*lmda(i)*(Cl))/16)+0.5)-sqrt((((rs*lmda(i)*(Cl))/16)+0.5).^2)-((rs*lmda(i)*(Cl).*(1-lmda(i).*pa(v)))/8);
Ct(i) = ((rs*lmda(i).^2*Cl)/2).*(((1-a(i))./1-pa(v)));
end
Z = imag(Ct);
for d = 1:1:201
if Z(v,d) ~= 0
Ct(v,d) = NaN;
end
end
end
plot (lmda,Ct)
legend('10','5','-0.1','-2','-5')
axis([0 20 0 1])
xlabel('\lambda');ylabel('C_t');title('Thrust coefficient against tip speed ratio.');
legend('\theta_T=10^{o}','\theta_T=5^{o}','\theta_T=-0.1^{o}','\theta_T=-2^{o}','\theta_T=-5^{o}')
J
J 2012-2-22
I changed it again, thanks so much for your help!
clear all
clc
rs=0.05;
Cl=2*pi;
pa=[(pi/18) (pi/36) -(pi/1800) -(pi/90) -(pi/36)];
for v=1:5
lmda=0:0.1:20;
Ct(v,:) = ((rs*lmda.^2*Cl)/2).*(((1-((rs*lmda*Cl/16+1/2)-...
((rs*lmda*Cl/16+1/2).^2-(rs*lmda*Cl.*(1-lmda*pa(v)))/8).^(1/2))))./lmda-pa(v));
Z= imag(Ct);
for d = 1:1:201
if Z(v,d) ~= 0
Ct(v,d) = NaN;
end
end
end
figure,plot(lmda,Ct)
grid on
axis([0 20 0 1]);
xlabel('\lambda');ylabel('C_t');title('Thrust coefficient against tip speed ratio.');
legend('\theta_T=10^{o}','\theta_T=5^{o}','\theta_T=-0.1^{o}','\theta_T=-2^{o}','\theta_T=-5^{o}');

3 个评论

And that's why I love MATLAB. Actually, one more thing I love about MATLAB that would help you right now: logical indexing.
All that stuff to NaN out anything with a nonzero imaginary part? Yeah, try this: Ct(imag(Ct)~=0) = NaN; (Do it after the loop, so you have to do it only once.)
And speaking of doing stuff outside the loop, move your lmda = ... before the loop -- no need to do the same thing 5 times. And notice the orange warning on the line Ct(v,:) = ...? It won't make a whole heap of difference in this case, but get into the habit of preallocating space for your arrays, when you know how big they will be. Ct = zeros(5,length(lmda)); before the loop.
J
J 2012-2-24
<3 haha teach me more! Why couldn't you be my lecturer!
Because MathWorks pays more :)
Maybe some of these suggestions might help you:
http://www.mathworks.com/matlabcentral/answers/8026-best-way-s-to-master-matlab

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