reading and writing a cell array in a parfor loop

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Moritz H
Moritz H 2016-8-9
评论： Moritz H 2016-8-10
Hey!
I just came across this and I don't quite understand it. Why is MATLAB complaining about dependencies in different loop iterations when I do something like this:
%minimum working example:
a = cell(100,2);
%fill first row with values;
a(:,1) = {ones(1,1)};
%c = a;
parfor i=1:size(a,1)
b = a{i,1}(1) + 2;
a{i,2} = b;
end
Why can't I read the row I am working on prior to writing in it? I am using the same i every time... Do I really have to copy the whole array to c and read from that to run this parallel?
Thank you!

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采纳的回答

Edric Ellis
Edric Ellis 2016-8-10
One of the restrictions of parfor is that for a sliced variable, you need to use precisely the same form of indexing each time you use that variable. This is described in the doc. To fix this, you need to make a slight change to ensure that you always index into a using a fixed index listing, like so:
parfor i=1:size(a,1)
arow = a(i,:);
b = arow{1}(1) + 2;
arow{2} = b;
a(i,:) = arow;
end
  1 个评论
Moritz H
Moritz H 2016-8-10
nice, thank you! I didn't know I had to use the exact same indexing. I thought, operating on the same row would be enough...

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