Evaluating Nested Function Handles

2016 8 15

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I have a function that I would like to define in steps. e.g.,

y1 = @(x) 1./sqrt(1 - x.^2);
y2 = @(x) 1./sqrt(1 + x.^2);
T = (y2 -y1)./(y2 + y1);

How can I directly evaluate T in terms of the underlying variable x, i.e. T(x)?

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per isakson 2016-8-15

Did you try

T = @(x) (y2(x) -y1(x))./(y2(x) + y1(x));

and

>> T(0.4)
ans =
   -0.0805
>> T(1)
ans =
   NaN
>> T(1-eps)
ans =
   -1.0000

Hasan Abbas 2016-8-16

Thanks Per!

It did the trick.

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