Picking value from CDF

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Georgios Vamvakopoulos
评论： Georgios Vamvakopoulos 2016-8-17
Hello Everyone,
I ploted a CDF which I attached in the post. My problem is that I want to pick the 68%, 95% and 99.7% of the observations and find the corresponding value from x axis. How can I have matlab to pick these values and store them?. The problem is that there are too many graphs and it is impossible to do this manually.

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Torsten
Torsten 2016-8-17
编辑：Torsten 2016-8-17
v_68 = interp1(probability,velocity,0.68);
v_95 = interp1(probability,velocity,0.95);
v_99_7 = interp1(probability,velocity,0.997);
where probability and velocity are the arrays defining the CDF curve.
Best wishes
Torsten.

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John D'Errico
John D'Errico 2016-8-17
编辑：John D'Errico 2016-8-17
It is just a piecewise linear function. You can use a tool like intersections (from the file exchange) to do this trivially. Thus, on of the curves will be the CDF, and the other "curve" will be a horizontal line. Since that line can be defined by two points, it is trivial to create and pass in also.
Alternatively, you can create the CDF as a pchip spline (use pchip to do this), then use slmsolve, as found in my SLM toolbox. Or, you could use slmeval, also in the SLM toolbox .
Since pchip will build a nice smooth interpolant, it may be your preference. Or not. Any of the alternatives I have outlined will work trivially and efficiently in only a very few lines of code.
Edit: I see that Torsten has pointed out you could use interp1 to solve the problem by inverting x and y. This approach will work IF the tails of that CDF are NOT absolutely constant.
However if the first few points on the CDF are exactly zero, or the last few points are exactly 1, then interp1 will fail. It will give an error that talks about needing a monotonic vector for x.
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Georgios Vamvakopoulos
Georgios Vamvakopoulos 2016-8-17
Thank you for your reply, Torsten solution works just fine for my problem :)
Have a nice day

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