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if a=[1,2,3,4] how can i get b=[ (1+2),(1+3​),(1+4),(2​+3),(2+4),​(3+4) ] using for loops,Thanks

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MSP
MSP 2016-8-18
编辑： per isakson 2017-1-1
a=[1,2,3,4]
b=[ (1+2),(1+3),(1+4),(2+3),(2+4),(3+4) ]
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MSP
MSP 2016-8-18
编辑：Fangjun Jiang 2016-8-18
a=[1 2 3 4 ]
b=zeros(1,10)
for i=1:length(a-1)
for(k=2:length(a))
if(i==k)
b=a(k+1)+a(i)
else
b=a(k)+a(i)
end
end
end
MSP
MSP 2016-8-18
the problem im having is how to access (k+1)th element of a and store them in variable b as rowvector

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采纳的回答

James Tursa
James Tursa 2016-8-18
编辑：James Tursa 2016-8-18
The limits on your first for-loop are not correct. In particular, length(a-1) is not the same as length(a)-1. And the limits on your second for-loop are incorrect as well. You need to start the second loop index at i+1, not hard-coded start at 2. Then, for simplicity, maybe just use a counter to update the appropriate index of b. So, make the following changes:
for i=1:length(a-1)
Make the upper limit length(a)-1 instead of length(a-1)
for(k=2:length(a))
Make the lower limit i+1 instead of 2 (and get rid of the outer parentheses)
if(i==k)
b=a(k+1)+a(i)
else
b=a(k)+a(i)
end
No need for an if-test here. Simply set the appropriate element of b to your sum. E.g.,
x = 0; % <-- Do this at the start of your code
:
x = x + 1; % <-- Increment the subscript counter (inside the inner loop)
b(x) = a(k) + a(i); % <-- Set the appropriate element of b to your sum

更多回答（1 个）

Guillaume
Guillaume 2016-8-18
Here's an answer without a loop. More efficient!
a = 1:4
b = sum(nchoosek(a, 2), 2) %use nchoosek(a, 2) to create [1 2; 1 3; 1 4; 2 3; etc.]
  2 个评论
MSP
MSP 2016-8-18
Thanks Guillaume.But would u pls provide the crude algorithm using for loops.I would like to clear my confusion regarding looping
J. Webster
J. Webster 2016-8-18
The purpose of homework is to work out things for yourself. Not to go on messageboards and try to get experts to do your work for you.

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