ENBW documentation is ambiguous/incorrect.

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Andrew Roscoe
Andrew Roscoe 2016-8-19
回答： Greg Dionne 2017-2-27
In the ENBW documentation page http://uk.mathworks.com/help/signal/ref/enbw.html#btrihsq-1, the enbw(window(N),Fs) function is described as returning the two-sided bandwidth (in Hz) of a window. As far as I can see, this is a correct statement and evaluates (for all w(i) in N samples)
ENBW * (Fs/N) = (N * sum(w(i)^2)/sum(w(i))^2) * (Fs/N)
But, the example code given in EquivalentRectangularNoiseBandwidthExample.m clearly contains the lines:
bw = enbw(hann(1000),Fs)
.
.
.
plots:plot(bw*[-1 -1 1 1],[-40 maxgain maxgain -40],'--')
Surely this is incorrect and the example should plot:
plots:plot(bw/2*[-1 -1 1 1],[-40 maxgain maxgain -40],'--')
Andrew

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Greg Dionne
Greg Dionne 2017-2-27
Looks like this is fixed now.

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