Creating a sequential order vector from an unknown size vector

Question

Tim Tuttle 2016-8-20

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https://ww2.mathworks.cn/matlabcentral/answers/300297-creating-a-sequential-order-vector-from-an-unknown-size-vector

评论： Tim Tuttle 2016-8-21

I'm creating a program that would take an unknown size vector from the user and create another vector by assigning a number in sequential order for each element in the vector.

For example, the user types in [2 8 4 6] I would like to create a vector that would read [1 2 3 4]. I can not use any for loops. I have tried using the length() and numel() option to start the count, but only get the actual size of the vector. Thank you for any help.

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Answer 1

Azzi Abdelmalek 2016-8-20

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   a=[2 8 4 6]
out=1:numel(a)

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Tim Tuttle 2016-8-21

Thank you for your help. I was trying to use numel(a):1:end without any luck.

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Answer 2

Star Strider 2016-8-21

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https://ww2.mathworks.cn/matlabcentral/answers/300297-creating-a-sequential-order-vector-from-an-unknown-size-vector#answer_232351

在 MATLAB Online 中打开

If you want it to automatically create both row and column vectors, depending on the dimension of the input vector, this works:

x1 = [2, 8, 4, 6];                                      % Row Vector
x2 = [2; 8; 4; 6];                                      % Column Vector
Vseq = @(x) cumsum(ones(size(x)));
v1 = Vseq(x1)                                           % Row Vector
v2 = Vseq(x2)                                           % Column Vector
v1 =
       1     2     3     4
v2 =
       1
       2
       3
       4