Creating a sequential order vector from an unknown size vector
显示 更早的评论
I'm creating a program that would take an unknown size vector from the user and create another vector by assigning a number in sequential order for each element in the vector.
For example, the user types in [2 8 4 6] I would like to create a vector that would read [1 2 3 4]. I can not use any for loops. I have tried using the length() and numel() option to start the count, but only get the actual size of the vector. Thank you for any help.
回答(2 个)
Star Strider
2016-8-21
If you want it to automatically create both row and column vectors, depending on the dimension of the input vector, this works:
x1 = [2, 8, 4, 6]; % Row Vector
x2 = [2; 8; 4; 6]; % Column Vector
Vseq = @(x) cumsum(ones(size(x)));
v1 = Vseq(x1) % Row Vector
v2 = Vseq(x2) % Column Vector
v1 =
1 2 3 4
v2 =
1
2
3
4
类别
在 帮助中心 和 File Exchange 中查找有关 Numeric Types 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!