how i average n values in array
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if i have data a and i want to mean or average every 10 values as 1:10, 2:11, 3:12 and as so on for length of data ?
采纳的回答
Walter Roberson
2016-8-21
mean(reshape(YourData, 10, []))
8 个评论
yasmeen hadadd
2016-8-21
yasmeen hadadd
2016-8-21
Mudassir Rafi
2016-8-21
编辑：Walter Roberson
2016-8-21
arr=1:100;
for i=1:91
a=(arr(i:i+9));
mean(a)
end
yasmeen hadadd
2016-8-21
Mudassir Rafi
2016-8-21
value of i should be 9 less than the last dimension of array (i.e.a in your case)
Walter Roberson
2016-8-21
cs = cumsum(YourData);
moving_average = (cs(10:end) - cs(1:end-9))/10;
Andrei Bobrov
2016-8-21
Hi Walter! Small correcting.
cs = cumsum(YourData(:));
moving_average = (cs(10:end) - [0;cs(1:end-10)])/10;
Walter Roberson
2016-8-21
Thanks, Andrei
更多回答（2 个）
Star Strider
2016-8-21
‘But i need overlap between the values as 1:10 then from 2:11 and so on’
Use a moving average filter:
Heart_pulse_avg = filter(ones(1,10), 10, Heart_pulse);
1 个评论
Steven Lord
2016-8-21
Andrei Bobrov
2016-8-21
a - your vector;
out = movsum(a,[0 9],'Endpoints','discard')/10;
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