hi, i use the following code . the output is 15 values , i want stored this values automatically in array in order to Call these values again

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mohammed elmenshawy
评论： Star Strider 2016-8-24
for sw=1:15
n=[10;20;30;40;50;60;70;80;90;100];phi=0.5;
s=2;
z0=0.4;
index=0;
o=10;
for nn=1:o
a=normrnd(0,s^2,n(nn),1);
z=zeros(n(nn),1);
z(1)=phi*z0+a(1);
for i=2:n(nn)
z(i)=phi*z(i-1)+a(i);
end
for i=2:n(nn)
g(i)=z(i)*z(i-1);
end
k=sum(g,2);
num= (n(nn)-2)*k;
for i=3:n(nn)
f(i)=z(i-1)*z(i-1);
end
p=sum(f,2);
den=(n(nn)-1)*p;
index=index+1;
ma(index)=n(nn);
phihat(index)=num/den;
end
for i=1:o
da(i)=(phihat(i)-phi)^2;
end
MSEreal=num2str((sum (da)/(o)),'% .10f')
end

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采纳的回答

Star Strider
Star Strider 2016-8-24
I would just do:
MSEreal(sw) =sum((da)/(o));
There’s absolutely no need to convert them to a string array, since you have to convert them back to numeric to use them later. If you want to round them to 10 digits to the right of the decimal, use the latest version of the round function, or this anonymous funciton to do the same thing:
roundn = @(x,n) round(x .* 10.^n)./10.^n; % Round ‘x’ To ‘n’ Digits, Emulates Latest ‘round’ Function

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