creating a perfect number function
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Hi. I am currently having a prob. I need to create a function that takes in the number(n) as argument and returns true if n is a perfect number. I am not allowed to use vectors and for loop for this question. I am stuck at this few codes:
function num = perfect(n)
i=1;
sum = 0;
while i <= n/2
if rem(n,i) == 0
else
i = i +1
end
sum = sum + i;
end
if n == sum
n = true
I am a beginner in Matlab and I require assistance. Any kind soul out there to help me? Thanks!
1 个评论
John D'Errico
2016-8-30
Using the name sum as a variable name will create problems down the road for you. Don't name variables the same as useful functions that you will later need. Or expect to see lots of bugs in your code. Of course, you might like buggy code. Your choice.
采纳的回答
Guillaume
2016-8-30
First and foremost, learn to use matlab's debugger. Step through your code, see how the variables change after each instruction, and check that the result was what you expected.
There is clearly a problem with your code. You have a while loop that essentially says:
while i is some value
if some condition
do nothing. Particularly, do not change i
else
change i
end
do something that does not change i
end
You can see that under some condition i never changes, so the loop will repeat infinitely. You need to fix that.
As per John's comment, don't use sum as a variable name, as you won't be able to use the sum function.
Also note that
if somecondition
else
do something
end
is better written as
if ~somecondition
do something
end
2 个评论
Fu Xiangli
2016-8-31
Guillaume
2016-8-31
Yes, that's much better.
One small improvement you can do is get rid of the final if and simply do:
num = n == factorsum;
更多回答（1 个）
alex usefi
2018-9-10
0 个投票
How to get numbers like this from the code? is_perfect(6)
show result code: 1 2 3
1 个评论
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