Attempted to access x(1,2); index out of bounds because size(x)=[105760,1].

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Manjutha Manavalan
Manjutha Manavalan 2016-8-31
评论： Walter Roberson 2019-7-3
can you please solve this sir
for i=1:2
for j=2:len-1
x(j,i) = (x(j-1,i) + x(j,i) + x(j+1,i))/3 ;
end
end
i am getting error command Attempted to access x(1,2); index out of bounds because size(x)=[105760,1].
Error in highfrequencynoiseremoval (line 14)
x(j,i) = (x(j-1,i) + x(j,i) + x(j+1,i))/3 ;

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Azzi Abdelmalek
Azzi Abdelmalek 2016-8-31
From the error message, it appears that your variable x is a a column vector 105760x1 . In your code you are trying to access x(1,2) which should be in the second column that doesn't exist
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shivam verma
shivam verma 2019-7-3
how you solve this problem can u tll me please. i m a beginner in the imag processing ..
Walter Roberson
Walter Roberson 2019-7-3
The original poster of the question looks to have created x as a column vector somehow. That could have occurred if they had used (:) or reshape() to force it to be a column vector. It could also have occurred if they were not careful in how they deleted some data from the array. For example if they used
x(1:5) = [];
instead of
x(1:5,:) = [];

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