operations on structer under specific conditions ?
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if there is a structure (S) for 10 nodes. the three fields of the structure are (xd , yd and ID) where,,
S.xd ==> X-dimension , S.yd ==> Y_dimension , S.ID ==> node's order or its ID , S.E ==> Energy
the distance between two nodes i and j equal D(i,j)= sqrt((S(i).xd-S(j).xd)^2+(S(i).yd-S(j).yd)^2).
i want to compare the distance between all nodes, hence if the distance between two nodes is less than specific value (do), we keep the higher energy nodes and neglect the other.
at the end we get the structure of the new higher energy nodes
回答（3 个）
You can find the distance between one node to other the other nodes using the following lines:
clc; clear all ;
N = 10 ;
for i = 1:N
s(i).id = i ;
s(i).x = rand(1,1) ;
s(i).y = rand(1,1) ;
end
%%distance between i'th node and other nodes
for i = 1:N
data = repmat([s(i).x s(i).y],[N,1])-[[s.x]' [s.y]'] ;
dist = sqrt(data(:,1).^2+data(:,2).^2);
%%Do what you want
end
KSSV
2016-9-1
That i snot a big deal...
clc; clear all ;
N = 10 ;
for i = 1:N
s(i).id = i ;
s(i).x = rand(1,1) ;
s(i).y = rand(1,1) ;
end
%%distance between i'th node and other nodes
for i = 1:N
data = repmat([s(i).x s(i).y],[N,1])-[[s.x]' [s.y]'] ;
dist = sqrt(data(:,1).^2+data(:,2).^2);
%%Do what you want
% get the indices whose distance is less then 0.5
idx = find(dist < 0.5) ;
nodes = [[s(idx).x]' [s(idx).y]']
end
Stephen23
2016-9-1
Rather than writing slow and ugly loops, you could simply use bsxfun:
do = 0.9;
S = struct(...
'xd',num2cell(rand(1,10)),...
'yd',num2cell(rand(1,10)),...
'E', num2cell(rand(1,10)));
%
hyp = bsxfun(@hypot,[S.xd].',[S.yd]);
idx = hyp<do
...etc
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2016-9-1
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