How to extract a specific 3 digit number from a filename?

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Mohammed
Mohammed 2016-9-1
评论： Kim Arnold 2020-2-7
I have this filename (hst_05773_05_wfpc2_f502n_wf_sci.tif) and i would like to extract the three digit number after the _f . i.e. 502, but i am not sure how to do that as i am a beginner in MATLAB Thanks in advance

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Azzi Abdelmalek
Azzi Abdelmalek 2016-9-1
编辑：Azzi Abdelmalek 2016-9-1
s='hst_05773_05_wfpc2_f502n_wf_sci.tif'
out=regexp(s,'(?<=_f)\d{3}','match','once')
or
s='hst_05773_05_wfpc2_f502n_wf_sci.tif'
idx=strfind(s,'_f')
out=s(idx+2:idx+4)
  2 个评论
Songman Liao
Songman Liao 2018-1-25
Hi Azzi, I actually have 24 files, 12 of them have names starting from "AMS1701-AMsent1.log" to "AMS1701-AMsent12.log". And the rest have names like "AMS1701.02-AMsent1.log" to "AMS1701.02-AMsent12.log". There are two kinds of number I want to extract. The first type is whether "AMS1701" with ".02" or without it. The second type of number is the number following "AMsent". Can you help me with that? Thank you so much!
Walter Roberson
Walter Roberson 2018-1-25
To detect the .02:
has_02 = isempty( strfind(filename, '.02') );
You are not clears as to what number you want to extract. I suspect you want the number before the '.log' part:
out = regexp(filename, '\d+(?=\.log)', 'match', 'once')
you could str2double() that if you wanted.

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更多回答（1 个）

Kim Arnold
Kim Arnold 2020-2-5
Hi everybody im quite new to Matlab.
How is it if you have like 1000 files. Do you first convert them to char characters? when i do it with one file with the name '20191108_1_blank_BA_pos.mzXML' as follows:
ix=strfind(Spos.Files_names(1),'_BA');
net=char(Spos.Files_names(1))
let=net(ix-3:ix-1)
it gives me the 3 letters before _BA, here "ank".I want to find the 3 letters before _BA for all the files. The code above allows me to do this for one file. Do i have to do a for loop and is there another ways instead of converting the files to type char?`
Thanks a lot!
  2 个评论
Walter Roberson
Walter Roberson 2020-2-5
dinfo = dir('*XML'); %not *.XML as the extension is mzXML for some reason
filenames = {dinfo.name};
lets = regexp(filenames, '...(?=_BA)', 'match', 'once');
lets will now be a cell array of character vectors, with one entry for each XML file found in the current directory, and the entry will be the 3 characters before _BA in the file name. To emphasize, lets will have done all of them at once, so lets{1} would be the first, lets{2} would be the second, and so on.
Kim Arnold
Kim Arnold 2020-2-7
Dear Walter,
Many thanks for your answer, this is much more effective than my for loop!

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