Storing values using csapi (spline functin)

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Mauricio Marulanda 2012-2-24

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编辑： dpb 2013-10-24

I have been trying to use csapi. This command will work: x = [0 1 2 3]; y = [0 1 2 3]; csapi(x,y); However, I am trying to let x be a cell array. x = {[0 1 2 3] [0 1 2 3]}; y = [0 1 2 3]; Basically I want my "x" to be a table with different values. csapi(x,y); will not work for this case. Is this possible? I appreciate any help.

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回答（2 个）

Sean de Wolski 2012-2-24

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Why not just use a for-loop?

Or you coudl write a wrapper function around csapi that uses a for-loop internally but allows you to call it with a cell array.

Just my $0.02

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Sean de Wolski 2012-2-24

If called correctly it will take a cell array:

doc csapi

Mauricio Marulanda 2012-2-24

according to the document as long as "if x is sequences x1, ..., xm, of lengths n1, ..., nm respectively, then y is expected to be an array, of size [n1,...,nm]"

then why st{1} = csapi({a,b,c,d},y); will not work if

x is a cell array and

y is pretty much (y1..length(a), y2..length(b), y3..length(c), y4..length(d))

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Mauricio Marulanda 2012-2-27

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I believe based on the comments the best way to do this: Come up with something like this. x = f(a,b,c,d) %refering to my previous code Where x is a unique function of a,b,c,d. y = [y1 y2 ... length(x)] %length(x) = length(a)*len(b)*len(c)*len(d) out = csapi(x,y)