My rectangle should have a determined color represented by a value

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Philipp Mueller
Philipp Mueller 2016-9-5
评论： Neda 2017-11-8
I have 2 patch objects which should be placed with a determined color (represented by a value). I did not implement it because I dont know how it works. So the rectangle 1 should have the value 50 and the rectangle 2 should have the value 75. The colorbar should start from 0 to 100. Thank you in advance.
v = [0 0; 1 0; 1 1; 0 1;5 5; 10 5;10 10;5 10];%Rectangle 1 and 2
f = [1 2 3 4; 5 6 7 8];
patch('Faces',f,'Vertices',v,'FaceColor','green')
colorbar

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采纳的回答

Stephen23
Stephen23 2016-9-5
编辑：Stephen23 2016-9-5
The easiest way is to use caxis, like this:
V = [0,0;1,0;1,1;0,1;5,5;10,5;10,10;5,10];
F = [1,2,3,4;5,6,7,8];
C = [50;75];
patch('Faces',F,'Vertices',V,'FaceVertexCData',C,'FaceColor','flat')
colormap(parula)
colorbar
caxis([0,100]) % set the color limits
which generate this (you can pick whatever colormap suits you best):
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https://www.mathworks.com/matlabcentral/answers/228557-experts-of-matlab-how-did-you-learn-any-advice-for-beginner-intermediate-users
  1 个评论
Neda
Neda 2017-11-8
How about if we need to change the colour of circle based on their values, and circle superimposed on the image with rectangle which does have 'Curvature',[1 1].

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更多回答（1 个）

Thorsten
Thorsten 2016-9-5
编辑：Thorsten 2016-9-5
50 and 75 are not valid colorvalues in Matlab. Valid is an RGB triplet in the range [0, 1]. So I assumed that 50 and 75 is an index into a colormap. I choose 'gray', but you can any other valid colormap, like 'parula' or 'jet', for example:
Nfaces = 2;
facecolind = [50 70];
cmap = gray(100);
for i = 1:Nfaces
patch('Faces',f(i,:),'Vertices',v,'FaceColor', cmap(facecolind(i),:))
end
colormap(cmap)
h = colorbar
h.TickLabels = h.Ticks*100
  3 个评论
显示 1更早的评论
Adam
Adam 2016-9-5
Sounds like you want the jet colourmap then. You could create your own to be more to your taste, but jet does run from blue through green up to red.

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