Write a function called halfsum that takes as input an at most two-dimensional array A and computes the sum of the elements of A that are in the lower right triangular part of A
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Write a function called halfsum that takes as input an at most two-dimensional array A and computes the sum of the elements of A that are in the lower right triangular part of A, that is, elements in the counter-diagonal (going from the bottom left corner, up and to the right) and elements that are to the right of it. For example, if the input is [1 2 3; 4 5 6; 7 8 9], then the function would return 38.
This is all I have so far:
function sum=halfsum(v)
sum=0;
[row col]=size(v);
for i= 1:row;
for j=1:col;
I have spent hours on trying to figure out how to sum the reverse diagonal starting at the bottom left element and everything to the right of it and cannot seem to figure it out. Any help is greatly appreciated!
6 个评论
nikhil singh
2020-4-26
This program is for calculating sum of upper triangle of a Matrix, hope it helps
function summa=halfsum(M)
[row column]= size(M);
summa=0;
sumdiagonal=0;
sumupper=0;
for i=1:row
for j=1:column
if i==j
sumdiagonal = sum(M(i,j))+ sumdiagonal;
end
if i<j
sumupper = sum(M(i,j)) + sumupper;
end
summa=sumdiagonal + sumupper;
end
end
end
Walter Roberson
2020-4-26
Is there a particular reason to sum the diagonal seperately from summing the upper part?
Soham Bhosale
2020-6-2
i think this program will help you for summing upper triangular part
function summa = halfsum(x)
[row,col] = size(x);
allsum=0;
for n=1:row
for c=n:col
allsum=x(n,c)+allsum;
end
end
summa=allsum;
TINOY SANTRA
2020-6-13
function summa=halfsum(A)
b=size(A);
row=b(1);
col=b(2);
summa=0;
for i=1:row
for j=1:col
if(i==j)
summa=summa+sum(A(i,j:end));
end
end
end
summa
TINOY SANTRA
2020-6-13
i did this code and it worked fine
Image Analyst
2020-6-13
Do not post up here. If you think that none of the 18 answers below and 2 answers above answer the question and that your answer offers something unique, then you can reopen the question to post your answer that is different than the prior 20 solutions.
采纳的回答
更多回答(17 个)
Vikrant Prasad
2019-3-22
function summa = halfsum(A)
[row, col]=size(A);
sum=0;
for i=1:row
for j=i:col
if i<=j
sum= sum + A(i,j);
end
end
end
summa =sum;
end
3 个评论
asad jaffar
2019-3-31
vikrant how to write it for uperright instead of lower right ?
Image Analyst
2019-3-31
编辑:Image Analyst
2019-3-31
Did you try
if i>=j
and it didn't work??? Or did you do
summa = sum(A(triu(A)))
You didn't use sum for the name of the variable, contrary to what I said in my answer, did you??
Please attach the code so we can check why it's not working.
mayank ghugretkar
2019-6-10
another similar way
1. with for loop
function summa=halfsum(A)
[row col]=size(A);
summa=0;
j=0;
for i=1:row
for j=1:col
if j>=i
summa= A(i,j) +summa;
end
end
end
end
2. with While loop
function summa=halfsum(A)
[row col]=size(A);
summa=0;
for i=1:row
j=i;
while (j>=i && j<=col)
summa= A(i,j)+ summa;
j=j+1;
end
end
summa;
end
i love trying this things... simplifying n solving
Prashanth Reddy Penta Reddy
2017-5-25
function u = halfsum(P)
u1 = P(end:-1:1, 1:end);
u2 = triu(u1);
u = sum(u2(:));
end
3 个评论
Jorge Briceño
2018-2-3
Hi everyone,
I solve the problem in a different way. Here it is:
function [counter] = halfsum (A)
% ii = rows ; jj = columns
[m,n]=size(A);
counter = 0;
ii=m;
for jj=1:n
if ii>0 % This contidion is mandatory, otherwise the ii could be equal zero, which will result in an error
counter=counter + sum(A(ii,jj:n)); % Function sum(A(ii,jj:n)) sums all the column in a row.
ii=ii-1; % This is equivalent to a row for loop.
end
end
counter;
end
Another way using rows and columns for loops would look like:
function [counter] = halfsum (A)
% ii = rows ; jj = columns
[m,n]=size(A);
counter = 0;
col=1;
for ii=m:-1:1
for jj=col:n
counter=counter + A(ii,jj);
end
col=col+1;
end
counter;
end
William Gallego
2018-11-3
编辑:William Gallego
2018-11-3
Great, I understood both ways. Actually, I spent most of my time trying to figure out the loop for ii=m:-1:1. I forgot to count backward :(. Thanks for the help!
Mukti Awad
2019-8-16
I am getiing this error!!!
Assessment result: incorrect[1 2 3; 4 5 6; 7 8 9]
Variable summa has an incorrect value.
Nijita Kesavan Namboothiri
2019-6-26
function summa=halfsum(m)
summa=0
[r c]=size(m)
for i=1:r
for j=1:c
if i<=j
summa=summa+m(i,j)
end
end
end
0 个评论
Image Analyst
2016-9-7
Try
theSum = 0; % DON'T USE sum as a variable name!!!
[rows, columns] = size(v);
for row = 1 : rows
for col = (columns - row + 1) : columns
theSum = theSum + .......
0 个评论
Justin Whetten
2016-12-13
For anyone who might be struggling still with this
function sum=halfsum(A);
sum = 0;
[row,col] = size(A);
for i= 1:row
for j=1:col
if (i+j)>=(row+1)
sum = sum + A(i,j);
end
end
end
2 个评论
Steven Lord
2016-12-13
There's no need for a test inside the loops.
In row 1, how many elements will be included in the sum and in which column are those elements located?
In row 2, how many elements will be included in the sum and in which column are those elements located?
Continue asking this question and see if there is a pattern to the answers that you can exploit in the definition of the second for loop to force only those elements that should be included in the sum to be included.
Image Analyst
2016-12-14
And of course, NEVER use "sum" as the name of your variable (as I mentioned in my answer) since that's the name of a very important built-in function that you won't be able to use anymore if you redefine "sum" to be your own personal variable.
And if you're puzzled by what Steve said, just see my answer.
MANAV MALHOTRA
2019-6-25
function summa=halfsum(m)
summa=0;
for i=1:size(m,1)
for j=1:size(m,2)
if(i<=j)
summa=summa+sum(m(i,j));
end
end
end
for those who are less familiar with matlab
0 个评论
Roshan Singh
2019-9-15
function summa=halfsum(a)
[r,c]=size(a);
summa=0;
for x=1:r
for y=1:c
if (x==y)||(x<y)
summa=a(x,y)+summa;
end
end
end
fprintf('summation of right hand matrix is...%d\n',summa)
end
1 个评论
Walter Roberson
2019-9-15
(x==y)||(x<y) is the same logical condition as x<=y but x<=y is more efficient.
Sebastián Añazco
2019-9-21
function summa = halfsum(A)
summa = 0;
for n = 1 : size (A,1)
for m = 1:size(A,2)
if n >m
a = 0;
else
a = A(n, m);
end
summa = summa +a;
end
end
0 个评论
Shubham Pandey
2020-4-3
function sum = halfsum(a)
sum = 0;
[row,col] = size(a);
for i=1:row
for j=1:col
if i<=j
sum=sum+a(i,j);
end
end
end
end
3 个评论
Shubham Pandey
2020-4-3
this works fine
Image Analyst
2020-4-3
But every MATLAB expert would advise anyone to never use the name of a built-in function like sum() as the name of a variable.
Shubham Pandey
2020-4-3
I agree with your feedback. Just a noobie mistake.
Nitin Kumar soni
2020-4-27
function summa=halfsum(n)
[row,col]=size(n);
summa=0;
for i=1:row
for j=1:col
if i<=j
summa=summa+n(i,j);
end
end
end
1 个评论
Walter Roberson
2020-4-28
You can avoid the if statement if you have j end at i instead of continuing to col.
Ashay Nagdive
2020-5-1
function a = halfsum(A)
[row col]= size(A);
a = 0;
for r= 1: row
for c= 1: col
if c >= r
a= a + A(r,c)
else
A(r,c)= 0;
end
end
end
0 个评论
SANTOSH KAMBLE
2020-5-4
function summa=halfsum(x)
[row col]=size(x);
summa=0;
for r=1:row
for c=1:col
y=x(r,c);
if r<=c
summa=summa+y;
end
end
end
end
0 个评论
ADARSH VISAJI
2020-5-9
function summa = halfsum(A)
[row, col]=size(A);
sum=0;
for i=1:row
for j=i:col
if i<=j
sum= sum + A(i,j);
end
end
end
summa =sum;
end
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my insta id:- visaji_adarsh
1 个评论
Image Analyst
2020-5-9
This is similar to most of the other answers however you used the function name "sum" as a variable. It is not recommended to overwrite built-in functions with variables because then you can never use the built in function name anymore within that scope. For example if you wanted to do
theSum = sum(1:100);
you would not be able to because you made sum a scalar number -- it's not the built-in function anymore.
Taif Ahmed BIpul
2020-5-15
function summa=halfsum(A)
[m,n]=size(A);
summ=0;
for i=1:m
for ii=i:n
summ=summ+A(i,ii);
end
end
summa=summ;
0 个评论
vighnesh rana
2020-5-19
function summa = halfsum(A)
[row col] = size(A);
total = 0;
for r = 1:row
for c= r:col
total = total + A(r,c);
end
end
summa = total;
end
0 个评论
Geetanjali Alle
2020-6-5
function summa = halfsum(M)
[row column]=size(M);
summa=0;
for i=1:row
for j=1:column
if i<j||i==j
summa=summa + sum(M(i,j));
end
end
end
Hope this helps!
1 个评论
Walter Roberson
2020-6-8
i<j||i==j
would be more efficient as
i<=j
There is also an easy change to prevent you from needing the if at all.
sum(M(i,j))
M(i,j) is a scalar. sum() of a scalar is the same scalar. You do not need sum() there.
AYUSH MISHRA
2020-6-11
function summa=halfsum(A)
[m,n]=size(A);
summa=0;
for i =1:m
fprintf('active row :%d \n',i);
for j=1:n
fprintf('active collumn :%d \n',j);
if m<=n
summa=summa+A(i,j);
end
fprintf('summa aeter every loop complition : %d \n',summa);
end
end
run it and understand every step working in loop
0 个评论
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