Save values in a loop in a vector

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Daniel
Daniel 2016-9-8
评论： mbonus 2016-9-12
Hi !
I would need some help for my home assignment cause im stucked. I need to iterate thru a vector and look for some values that are equal to 1.00, 0.80, 0.60, 0.40, 0.20 and 0.10. Then i need to store those values in another vector, how do i do this? Below u see the code for plotting those but i need to save them all in a vector so that i can make a nice table!
for i=1:size(d)
if d(i)==1.00000
disp(h(i))
elseif d(i)==0.80000
disp(h(i))
elseif d(i)==0.60000
disp(h(i))
elseif d(i)==0.40000
disp(h(i))
elseif d(i)==0.20000
disp(h(i))
elseif d(i)==0.10000
disp(h(i))
end
end

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回答（2 个）

mbonus
mbonus 2016-9-8
编辑：mbonus 2016-9-8
before the loop
v = zeros(size(d));
then just insert this line for each part of the if structure
v(i) = d(i);
If you need to get rid of the indexes with no values you can do this after the loop
v(find(0)) = [];
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Daniel
Daniel 2016-9-9
and result i get is all i positions in vector d which is == to 1.00, 0.80 and so on. But what i need is to use those i`s and save the values in z(i) in a new vector Z
mbonus
mbonus 2016-9-12
Could post an example of what you get and what it should look like?

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Thorsten
Thorsten 2016-9-9
I found it a bit hard to understand what your are looking for. As far as I understood, this can solve your problem:
p = [1.00, 0.80, 0.60, 0.40, 0.20, 0.10];
for i = 1:numel(p) % for all values in p
Z{i} = z(h == p(i)); % find all positions in h that equal p(i), and assign the corresponding positions in z to a new variable Z
end
  2 个评论
Daniel
Daniel 2016-9-9
For exampel: I have d=[1 22 31 41 51 6 7 8 9 10]; z=[1 2 3 4 5 6 7 8 9 10];
Now, i want to search in d for a value of 41. Then, give me that position, which in this case is on fourth column, hence i = 4
Now, go into the z vector and find me the value of column 4 and take that value and place it into Z vector :)
Thorsten
Thorsten 2016-9-9
编辑：Thorsten 2016-9-9
Z = z(d==41)
In my code above d == h and p(i) == 41. Because there can be, depending on your data, in principle one, two, or even more matches for d== 41, you have to store one, or two, etc values in Z, i.e., a different number of values for each i. That's why I use Z{i}. If you can guarantee that there is always one and only one match for each i, you can use Z(i).

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