error using zeros,integers problem
5 次查看(过去 30 天)
显示 更早的评论
i have this code
x = 1 +((riskf_end - riskf_start)/riskf_step);
y = 1 +((volatility_end - volatility_start)/volatility_step);
A = zeros(1 + x, 1 + y);
x and y are integers but the output of y is in exp notation and the 'zeros' command takes y as non integer. i can't figure this out.I tried 'format long g' but again the matrix does not recognize y as an integer.
ex.
riskf_end = 0.04
riskf_start = 0
riskf_step = 0.001
volatility_start = 0.13
volatility_step = 0.0001
volatility_end = 0.25
when putting volatility_step = 0.001 the problem disappears, but for smaller steps it apears again.x and y are always integers as the step will always be smaller than the boundaries. I would appriciate any help.Thanks in advance.
0 个评论
采纳的回答
Mischa Kim
2016-9-9
Why not simply round the numbers, e.g.
A = zeros(1 + round(x), 1 + round(y));
4 个评论
Guillaume
2016-9-9
编辑:Guillaume
2016-9-9
@Kostas, I think you misunderstood Mischa. He's telling you to round the inputs you give to the zeros function (so x and y), not your original values ( the riskf_* and volatility_* which obviously have to stay what they are).
The problem you are encountering is that, even if the numbers are symbolically integer, since computers can only store an approximate representation of most numbers, you have small rounding errors that means the result of calculation is often not exactly integer. As point out by Mischa, your y is 0.00000000000181... off from the integer 12001.
You can't avoid that, so if the result is meant to be integer, simply round it to integer.
Note that playing with format will have absolutely no effect on the actual value of the number. format only changes the way matlab displays numbers to you, not how they are stored in memory.
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!