finding some specific numbers in a numeric cell array
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I have a cell array that its cells contain numeric arrays of different sizes. each numeric array contains various number of numbers ranging from 7 to 13. i want to find the number and location of occurrences of all the 7s,8s,9s ...and 13s in the whole cell array. i used the following function:
I = cellfun(@(x) find(x==7), new_data, 'UniformOutput', false);
for finding 7 for example. new_data is my array. i encounter this error after running it:
Undefined function or method 'eq'for input arguments of type 'cell'.
can any body help me in this regard?
2 个评论
Adam
2016-9-13
Are you sure you don't have nested cell arrays rather than numeric arrays inside your outer cell array?
Andrei Bobrov
2016-9-13
Please show small example of your array cells.
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dpb
2016-9-13
Looks like you've nested the cell array; either create an array of cells with the double arrays each per cell or dereference inside your anonymous function--example:
>> dat(1)={randi([7 13],10,1)}; % make sample cell array
>> dat(2,1)={randi([7 13],8,1)}; % two cells w/ a double array in each
>> whos dat
Name Size Bytes Class Attributes
dat 2x1 264 cell
>> dat
dat =
[10x1 double]
[ 8x1 double]
>> cellfun(@(x) find(x==7), dat, 'UniformOutput', false)
ans =
[3x1 double]
[ 5]
>> ans{:}
ans =
7
9
10
ans =
5
>> data={dat} % now nest that in a single cell...
data =
{2x1 cell}
>> cellfun(@(x) find(x==7), data, 'UniformOutput', false)
Undefined function 'eq' for input arguments of type 'cell'.
Error in @(x)find(x==7)
>>
Look familiar??? :)
>> cellfun(@(x) find(x==7), data{:}, 'UniformOutput', false)
ans =
[3x1 double]
[ 5]
>> whos data
Name Size Bytes Class Attributes
data 1x1 324 cell
>>
NB: The curlies "{:}" to dereference the content of the cell in the latter...
8 个评论
zahra zol
2016-9-13
And why doesn't the solution shown provide precisely that?
If you're still having trouble, we need to see the details of what
whos new_data
shows so we can tell what the actual structure looks like altho it would seem as I demonstrated it's the latter of a cell array within a cell given the illustration of how the specific error you received can be generated. That's not the only way, certainly, but it's about the easiest to have created (perhaps inadvertently); showing how you created the data in the first place could lead to folks here being able to show simplifications in that as well.
zahra zol
2016-9-14
Your command works fine for me on your data if you remove the last 3 columns, though obviously not if you just try to run it on the whole matrix.
i.e.
cellfun(@(x) find(x==7), new_data(:,1:6), 'UniformOutput', false)
zahra zol
2016-9-14
Adam
2016-9-14
find returns the index of the found item so 13 is at index 5 in each of those arrays.
If you just want to know that the value exists and not where it is then use:
cellfun(@(x) ~isempty( find(x==13) ), new_data(:,1:6));
You also don't need the UniformOutput as false in that case as the output will be a logical array.
zahra zol
2016-9-14
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