Clustering data from index
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Good morning, I have a matrix like this
ID =
10032 10033
10140 10141
10604 10607
10610 10611
10615 10626
11199 11201
11200 11203
11279 11365
11283 11380
11605 11606
11635 11972
1168 1169
11 382
11 505
11 617
11 761
11 975
975 1320
3000 617
And I want to get all the families for which a same shared number is available for example a family will contain all these couples:
family = [11 382;
11 505;
11 617;
11 761;
11 975;
975 1320;
3000 617]
Do you have any idea about how to cluster this data?
Thanks in advance!
回答(2 个)
KSSV
2016-9-16
k = mode(ID(:,1)); % Gets most frequent number
idx = find(ID(:,1)==k) ; % get the indices where k=11 is
iwant = ID(idx,:)
1 个评论
Piero Poli
2016-9-16
编辑:Piero Poli
2016-9-16
Andrei Bobrov
2016-9-16
[a,~,c] = unique(ID);
out = ID(any(ismember(ID,a(accumarray(c,1) > 1)),2),:);
2 个评论
Piero Poli
2016-9-16
Andrei Bobrov
2016-9-18
function cl = fun_for_piero(ID)
[a,~,c] = unique(ID);
ii = reshape(c,size(ID));
k = 1;
i1 = 1;
cl{k} = [];
c = 1:numel(a);
while ~isempty(ii)
t = any(ismember(ii,i1),2);
if ~any(t)
k = k + 1;
cl{k} = [];
i1 = c(1);
else
p = unique(ii(t,:));
cl{k} = [cl{k};sort(a(p(:)))];
ii = ii(~t,:);
c = setdiff(c,p);
i1 = p(:);
end
end
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